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Amanda [17]
3 years ago
5

Help please and thanks

Mathematics
2 answers:
damaskus [11]3 years ago
7 0
Since the number 5 is in the Hundred Thousand place, i think the answer is:

500000
Mariana [72]3 years ago
5 0

Answer:

5 hundred thousand.

Step-by-step explanation:

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84÷0.02 samarian Roberts is very awsome and cool
insens350 [35]

0.02 can go into 84, 4200 times. Your answer is <u>incorrect</u>, the <u>correct answer</u> is 4200.

3 0
3 years ago
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Find the sum of the finite geometric series: 5 + 10 + 20 + ... +81,920.
Anestetic [448]

Answer:

No solution

Step-by-step explanation:

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequence by  2  gives the next term. In other words,  <em>a n +a1 ⋅ r n -1</em><em> </em>

Geometric Sequence:<em>  </em><em>r = 2</em>

The series given has a value of<em>  </em><em>r  </em>such that <em>r  >  1  or   r  <  −  1.</em> Therefore, the infinite sum cannot be calculated.<em> </em>

<em> </em>

<em> </em>

8 0
2 years ago
Find the equation of the line through M parallel to 3x+y=18
love history [14]

Answer:

3x+y=18

3xy=18

xy= 18/3

xy=6

5 0
3 years ago
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Robert accepted a new job at a company with a contract guaranteeing annual raises. Let S represent Robert's salary after working
vesna_86 [32]

Answer:

74,000

Step-by-step explanation:

In the year where he got 104,000 the year before he got 6,000 less. The year before 98,000 he got 12,000 less which means that now it would just be 86,000-12,000=74,000

I think this is right but you can double check on a calculator

Hope this helped!

6 0
2 years ago
Write a recursive formula for each sequence given or described below.
valentinak56 [21]

Answer:

a_{n} =a_{n-1} +3000 and a₁ =30000 for n = 2,3,4,5,6, ......

Step-by-step explanation:

Doug has joined a job with a starting salary of $30000 per year.  

Hence, if a₁ is the salary of Doug in the first year, then  

a₁ =30000

Now, each year Doug will receive a raise of $3000 in his salary.

Hence, in the 2nd year, his salary(a₂) will become ( a₁ +3000) per year.

Again, in the 3rd year, his salary(a₃) will become ( a₂ +3000) per year.

Therefor, in the similar manner the recursive formula for his salary in each year will be given as a_{n} =a_{n-1} +3000 and a₁ =30000 for n = 2,3,4,5,6, ...... {aₙ is the yearly salary of Doug in the nth year} (Answer)

7 0
3 years ago
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