All categories

3 years ago

2/3x- 1/5 is greater than 1

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

8 0

Answer:

Step-by-step explanation:

$\dfrac{2}{3}x-\dfrac{1}{5}>1\qquad\text{multiply both sides by 15}\\\\15\!\!\!\!\!\diagup^5\cdot\dfrac{2}{3\!\!\!\!\diagup_1}x-15\!\!\!\!\!\diagup^3\cdot\dfrac{1}{5\!\!\!\!\diagup_1}>15\cdot1\\\\(5)(2x)-3>15\qquad\text{add 3 to both sides}\\\\10x>18\qquad\text{divide both sides by 10}\\\\\boxed{x>1.8}$

lora16 [44]3 years ago

5 0

Answer:

X > 9/5

Step-by-step explanation:

Just did it

You might be interested in

What is 5 times a number minus 3 is 12 ?

Rom4ik [11]

Answer:

5*x-3=12

the number is 3 because 5*3=15 and 15-3=12

8 0

2 years ago

Read 2 more answers

Please help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Flura [38]

Answer:

#6 is 17 days

Step-by-step explanation:

This is how I answered it

1) 2750 = 550 + 125x

2) subtract 550 from each side

2750-550=2200

so the left over equation is:

2200 = 125x

3) divide each side by 125 to get x by itself

2200÷125= 17.6

4) you are left with: x = 17 days

6 0

2 years ago

PLEASE HELP!!! GEOMETRY<br> please

Cloud [144]

Nothing else is given, so for the two triangles to be congruent, the only possible proof is the ASA theorem.
first pairs of angles: 2x+7=x+21 => x=14
second pairs of angles: 8y-4=4y+28 =>y=8
The two triangles share the same side PR
Based on the Angle-Side-Angle Triangle Congruence theorem, these two triangles are congruent with x=14, y=8
(2x+7) +(8y-4) +Q=180 =>85

4 0

2 years ago

What is always the smallest positive factor of any positive integar?

Ulleksa [173]

Answer:

Step-by-step explanation:

The smallest positive factor is 1

But not 0 because 0 is not positive nor negative

4 0

2 years ago

Which of the following functions gives the length of the base edge, a(v), of a right square pyramid that is 8 inches tall as a f

Reil [10]

Answer:

$\large\boxed{a(V)=\sqrt{\dfrac{3V}{8}}}$

Step-by-step explanation:

The formula of a volume of a square pyramid:

$V=\dfrac{1}{3}a^2h$

a - base edge

h - height of a pyramid

We have H = 8in.

Substitute and solve for a:

$\dfrac{1}{3}a^2(8)=V\\\\\dfrac{8}{3}a^2=V\qquad\text{multiply both sides by}\ \dfrac{3}{8}\\\\\dfrac{3\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}\cdot\dfrac{8\!\!\!\!\diagup^1}{3\!\!\!\!\diagup_1}a^2=\dfrac{3}{8}V\\\\a^2=\dfrac{3V}{8}\Rightarrow a=\sqrt{\dfrac{3V}{8}}$

3 0

3 years ago