Answer
Let f(x) = ax + b
Then
f(x + 1) = a(x + 1) + b
= ax + a + b
Hence, a = 3, and a + b = 5, b = 2
f(-2) = 3(-2) + 2
= -6 + 2
= - 4
f(2x) = 3(2x ) + 2
= 6x + 2
Answer:
216
Step-by-step explanation:
Im taking the topic assessment rn
Answer:x>7 or x ≤ -3
Solving the 1st inequality
-6x +14 < -28 --------------- (Collect like terms)
-6x < -28 - 14
-6x < - 42 -------------------- (Divide both sides by -6)
Note: If you decide an inequality expression by a negative value, the inequality sign changes)
-6x/-6 > -42/-6
x > 7
Solving the 2nd inequality
9x + 15 ≤ −12 ----------- (Collect like terms)
9x ≤ −12 - 15
9x ≤ −27 ------------------(Divide both sides by 9)
9
9x/9 ≤ −27/9
x ≤ -3
Bring both results together, we get
x>7 or x ≤ -3
The final result is complex (i.e. can't be combined together).
Step-by-step explanation:
It would be 7x hope this helps
The answer to the question is the first, third and fifth
