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elena55 [62]
3 years ago
10

Use substitution

gn="absmiddle" class="latex-formula"> to find all 4 roots of z^{4} + z^{2} + 1
Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0

Answer:

4

+

3

+

2

+

+

1

=

0

Step-by-step explanation:

Answered about

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A formula for finding the perimeter of a rectangle is P=2L +2W . if you know the perimeter (P) and the length (L) of a rectangle
Neko [114]
The original equation is
P=2L+2W

We will just switch the unknowns around. To find width (W), we must isolate it in the equation by moving 2L over to the other side:

P-2L=2W

(P-2L)/2=W

W=(P-2L)/2

There you go!!

If this is helpful, please mark me brainliest. :)
5 0
3 years ago
Multiply (-4)(-2)(-5)<br> A= -40<br> B= -8<br> C= 8<br> D= 40
Aneli [31]

Answer:

-40

Step-by-step explanation:

just multiply and add the negitive signs

5 0
4 years ago
Read 2 more answers
The letters in the word January are put into a bag drawn randomly what is the probability of an A?
Helga [31]

Answer:

1/49 or 1/42

Step-by-step explanation:

if the letters are put back you would have a 2/7 chance of drawing the letter a each time but if they aren't replaced then you would have a 2/6 chance of getting a

3 0
3 years ago
Can someone help me with this question? Whoever helps will get brainliest answer. thank you.
enyata [817]

Answer:

Final answer is x^2.

Step-by-step explanation:

Given expression is x^{\left(\frac{4}{3}\right)}\cdot x^{\left(\frac{2}{3}\right)}

Now we need to find about what is product of both factors.

We see that both factors are in exponent form having equal base "x".

So we can apply formula: x^m\cdot x^n=x^{\left(m+n\right)}

x^{\left(\frac{4}{3}\right)}\cdot x^{\left(\frac{2}{3}\right)}

=x^{\left(\frac{4}{3}+\frac{2}{3}\right)}

=x^{\left(\frac{4+2}{3}\right)}

=x^{\left(\frac{6}{3}\right)}

=x^2

Hence final answer is x^2.

5 0
3 years ago
Twenty-five percent of the students in a class received a grade of 85 and
tatyana61 [14]

Answer:

9

Step-by-step explanation:

36÷4=9.................

8 0
3 years ago
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