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2 years ago

Identify the domain of an image that has been rotated 270 degrees counter-clockwise

Mathematics

1 answer:

tensa zangetsu [6.8K]2 years ago

8 0

Answer:

A, (4,-3), (1, -1), (7,-6)

Step-by-step explanation:

f(x, y) = (y, -x) there is a 90° clockwise or 270° counterclockwise rotation

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A glacier covered about 176 acres in 2006 and was shrinking at a rate of about 3.7% per year.

Alex777 [14]

Answer:

a) S=-6.512t+176

b) 123.904

c) 13.024

Step-by-step explanation:

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2 years ago

Martha needs 22.25 strawberries for every 5 smoothies she makes. Complete the table to see how many strawberries she would need

Nezavi [6.7K]

44.50 strawberries for 10 smoothies
89 strawberries for 20

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2 years ago

What is a unit rate?

REY [17]

A unit rate in math is the expression of a rate in a quantity of one. For example, 60 miles per hour represents a commonly used unit rate. Similarly, 30 students per school bus also represents a unit rate.

5 0

2 years ago

A group of 59 randomly selected students have a mean score of 29.5 with a standard

algol [13]

Answer:

$29.5-1.671\frac{5.2}{\sqrt{59}}=28.37$

$29.5+1.671\frac{5.2}{\sqrt{59}}=30.63$

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

Step-by-step explanation:

Information given

$\bar X = 29.5$ represent the sample mean

$\mu$ population mean

s= 5.2 represent the sample standard deviation

n=59 represent the sample size

Confidence interval

The confidence interval for the true mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=59-1=58$

The Confidence interval is 0.90 or 90%, the significance is $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value is $t_{\alpha/2}=1.671$

Now we have everything in order to replace into formula (1):

$29.5-1.671\frac{5.2}{\sqrt{59}}=28.37$

$29.5+1.671\frac{5.2}{\sqrt{59}}=30.63$

And we can conclude that the true mean for the scores are given by this interval (28.37; 30.63) at 90% of confidence

8 0

2 years ago

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

denpristay [2]

Answer:

(1) Correct option is B.

(2) Correct option is C.

Step-by-step explanation:

The information provided is:

$n_{1}=200,\ \bar x_{1}=22.7,\ s_{1} = 4.5\\n_{2}=200,\ \bar x_{2}=19.7,\ s_{2} = 4.3$

The (1 - α)% confidence interval for the difference between two mean is:

$CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_[2}-2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}} }$

The critical value of t is:

$\alpha /2=0.05/2=0.025$

degrees of freedom $=n_{1}+n_{2}-2=200+200-2=398$

$t_{\alpha/2, n_{1}+n_{2}-2}=t_{0.025, 398}=1.96$

Compute the 95% confidence interval for the difference between two mean as follows:

$CI=22.7-19.7\pm 1.96\sqrt{\frac{4.5^{2}}{200}+\frac{4.3^{2}}{200} }\\=3\pm0.8624\\=(2.1376, 3.8624)\\\approx(2.14, 3.86)$

Thus, the 95% confidence interval, (2.14, 3.86) implies that the true mean difference value is contained in this interval with probability 0.95.

Correct option is B.

The null value of the difference between means is 0.

As the value 0 is not in the interval this implies that there is a difference between the two means, concluding that priming does have an effect on scores.

Correct option is C.

4 0

3 years ago