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Vladimir [108]
3 years ago
14

A hot air balloon is flying at an altitude of 2981 feet. If the angle of depression from the pilot in the balloon to a house on

the ground below is 26°, how far is the house
from the pilot?
Mathematics
1 answer:
dalvyx [7]3 years ago
7 0

Answer:

is 5668.3

Step-by-step explanation:

hope this helps

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Roma selects cards from a standard of 52 cards. Once a card is selected, it is not replaced. Find the probability of each outcom
meriva

Given:

A card is selected randomly from a standard deck of 52 cards.

To find:

The probability of each outcome.

a. a king of heart

b. a queen of spades

c. an ace of flower

d. an ace of diamond​

Solution:

In a standard deck of 52 cards.

Total number of cards = 52

13 cards of each suit (heart, diamond, club, spade).

13 cards are Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King.

a. We need to find the probability of getting a king of heart.

Number of king of heart = 1

P(\text{a king of heart})=\dfrac{\text{Number of king of heart}}{\text{Total cards}}

P(\text{a king of heart})=\dfrac{1}{52}

b. We need to find the probability of getting a queen of spades.

Number of queen of spades = 1

P(\text{a queen of spades})=\dfrac{\text{Number of queen of spades}}{\text{Total cards}}

P(\text{a queen of spades})=\dfrac{1}{52}

c. We need to find the probability of getting an ace of flower (spades).

Number of ace of flower = 1

P(\text{an ace of flower})=\dfrac{\text{Number of ace of flower}}{\text{Total cards}}

P(\text{an ace of flower})=\dfrac{1}{52}

d. We need to find the probability of getting an ace of diamond​.

Number of ace of diamond​ = 1

P(\text{an ace of diamond​})=\dfrac{\text{Number of ace of diamond​}}{\text{Total cards}}

P(\text{an ace of diamond​})=\dfrac{1}{52}

Therefore, the required probabilities for each parts are:

(a) \dfrac{1}{52}

(b) \dfrac{1}{52}

(c) \dfrac{1}{52}

(d) \dfrac{1}{52}

4 0
3 years ago
Answer only if you know<br><br> HELP PART A AND PART B
VARVARA [1.3K]

Answers:

  • Part A) There is one pair of parallel sides
  • Part B) (-3, -5/2) and (-1/2, 5/2)

====================================================

Explanation:

Part A

By definition, a trapezoid has exactly one pair of parallel sides. The other opposite sides aren't parallel. In this case, we'd need to prove that PQ is parallel to RS by seeing if the slopes are the same or not. Parallel lines have equal slopes.

------------------------

Part B

The midsegment has both endpoints as the midpoints of the non-parallel sides.

The midpoint of segment PS is found by adding the corresponding coordinates and dividing by 2.

x coord = (x1+x2)/2 = (-4+(-2))/2 = -6/2 = -3

y coord = (y1+y2)/2 = (-1+(-4))/2 = -5/2

The midpoint of segment PS is (-3, -5/2)

Repeat those steps to find the midpoint of QR

x coord = (x1+x2)/2 = (-2+1)/2 = -1/2

y coord = (x1+x2)/2 = (3+2)/2 = 5/2

The midpoint of QR is (-1/2, 5/2)

Join these midpoints up to form the midsegment. The midsegment is parallel to PQ and RS.

7 0
3 years ago
Answer these please!
neonofarm [45]

Answer:

u shouldnt wasnt your points u know

Step-by-step explanation:

3 0
3 years ago
Add and simplify <br> 9/10 + 1/9
arlik [135]

Answer:

1

Step-by-step explanation:

81/90 + 9/81 = 90/90 = 1

3 0
3 years ago
Please help me I WILL REPORT YOU FOR A LINK OR UNHELPFUL ANSWER i give brainliest
Vinvika [58]

the answer is x = -2

8 0
3 years ago
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