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3 years ago

Pls help I’ll brainlest

Mathematics

1 answer:

Helen [10]3 years ago

3 0

The cat is not hungry, or doesn't like the can of tuna food, which is why they refused to eat it when it was given to them.

Try to give the cat the food again and see their reaction, if that fails, try to give the cat other foods and note the reaction to determine if the cat just doesn't like the tuna in a can or just wasn't hungry at the moment.

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10 x 10 - 4 divided by 7

TEA [102]

Answer:

13.7142857143

Step-by-step explanation:

If you need to round then do so, or i will comment the rounded version if needed.

3 0

3 years ago

Three Less Than Is<br> Number 15

S_A_V [24]

Answer:12

Step-by-step explanation:

15-3=12

5 0

3 years ago

What is the equation of the circle with center (−3, 1) that passes through the point (−5, 3)?

Mariulka [41]

Answer:

( x + 3)^2 + ( y - 1)^2 = 8

Step-by-step explanation:

The equation of a circle with a center and a point

( x - a) ^2 + ( y - b) ^2 = r^2

( x , y) - any point on the circle

( a, b) - center of the circle

r^2 - radius of the circle

( -3 , 1) - center - ( a, b)

a = -3

b = 1

( -5 , 3) - point - ( x, y)

x = -5

y = 3

Step 1: substitute the center into the equation

( x -(-3)^2 + ( y - 1)^2 = r^2

( x + 3)^2 + ( y - 1)^2 = r^2

Step 2 : sub the point into the equation

( x + 3)^2 + ( y - 1)^2 = r^2

( -5 + 3)^2 + ( 3 - 1)^2 = r^2

(-2)^2 + 2^2 = r^2

4 + 4 = r^2

8 = r^2

Step 3 : sub the radius into the equation

( x + 3)^2 + ( y - 1)^2 = r^2

( x + 3)^2 + (y - 1)^2 = 8

Therefore, the equation of the circle is

( x + 3)^2 + (y - 1)^2 = 8

6 0

3 years ago

What is the area of this trapezoid?

timofeeve [1]

Answer: 140 $in^{2}$

Step-by-step explanation:

The area for a trapeziod is A = $\frac{1}{2}$ (b1+b2)h

We have almost everything we just need the total length of the top base, since it gives us the outer lengths we can find that by simply doing 4+6+15 which turns out to be 25

Now we can plug in our values:

A = $\frac{1}{2}$ (25 + 15) x 7 = 140 $in^{2}$

8 0

3 years ago

Read 2 more answers

M is the midpoint of JK. Find the coordinates of K. J(0, 11), M(-3,2)

cluponka [151]

Let's assume

point K as (x,y)

M is the midpoint of JK

so, other point as J(0, 11)

M(-3,2)