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Svetllana [295]
3 years ago
11

2x^2-2x-4=0 solve for x

Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0
Divide both sides by 2 and rewrite too X^2 - x - 2 = 0. then factor and get x(x+1)-2(x+1)=0. separate them to (x+1)(x-2)=0 then you get x+1=0 and x-2=0 and solve and X equals -1 & 2
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Solve the given initial-value problem. x^2y'' + xy' + y = 0, y(1) = 1, y'(1) = 8
Kitty [74]
Substitute z=\ln x, so that

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dz}\cdot\dfrac{\mathrm dz}{\mathrm dx}=\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)

Then the ODE becomes


x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}+x\dfrac{\mathrm dy}{\mathrm dx}+y=0\implies\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)+\dfrac{\mathrm dy}{\mathrm dz}+y=0
\implies\dfrac{\mathrm d^2y}{\mathrm dz^2}+y=0

which has the characteristic equation r^2+1=0 with roots at r=\pm i. This means the characteristic solution for y(z) is

y_C(z)=C_1\cos z+C_2\sin z

and in terms of y(x), this is

y_C(x)=C_1\cos(\ln x)+C_2\sin(\ln x)

From the given initial conditions, we find

y(1)=1\implies 1=C_1\cos0+C_2\sin0\implies C_1=1
y'(1)=8\implies 8=-C_1\dfrac{\sin0}1+C_2\dfrac{\cos0}1\implies C_2=8

so the particular solution to the IVP is

y(x)=\cos(\ln x)+8\sin(\ln x)
4 0
3 years ago
Marcos's grandparents gave Marcos a visa gift card of $250. Marcos decided to use his gift card to buy himself a fifteen dollar
Dimas [21]

Answer:

A) 250-50+x

B) Yes

C) 5

5 0
3 years ago
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A single rectangular pyramid is sliced parallel to the base as shown
n200080 [17]

A) 2

im not sure about my answer but ihope it will help u

8 0
3 years ago
2a + 2b = y <br><br><br> Solve for the variable, a
Eduardwww [97]
2a=y-2b
a=y-2b/2
a=y/2 -b

hope this helps !
5 0
3 years ago
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Zena needs a salesperson. Salesperson A is offering his services for an initial $100 in addition to $5 per hour. Salesperson B i
77julia77 [94]

Answer:

Step-by-step explanation:

The correct question is

Zena needs a salesperson. Salesperson A is offering his services for an initial $50 in addition to $5 per hour. salesperson B is offering her services for an initial $40 in addition to $7 per hour. When will the two coaches charge the same amount of money?

Let

x ----> the number of hours

y ----> the total charge

we know that

Salesperson A

------> equation A

Salesperson B

------> equation B

To find out when the two coaches charge the same amount of money, equate equation A and equation B and solve for x

7x+40=5x+50

7x-5x=50-40

2x=10

<h2>x=5 hours i think just im not sure but i tried</h2>
7 0
3 years ago
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