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Rama09 [41]
3 years ago
10

Marcos's grandparents gave Marcos a visa gift card of $250. Marcos decided to use his gift card to buy himself a fifteen dollar

lunch every day.
Marcos’s parents also gave Marcos a gift card but for his birthday. The gift card balance is represented by the equation: 50y + 55x = 500

(a. What equation represents Marcos's spendings that include his gift card?
(b. Will Marcos’ grandparent's and parents’ gift cards ever have the same balance?
(c. Determine the number of solutions Marcos’ parents and grandparents have.
Mathematics
2 answers:
Oksanka [162]3 years ago
6 0
A) would be 250-50+x
B) would be yes
C) would be 5
Dimas [21]3 years ago
5 0

Answer:

A) 250-50+x

B) Yes

C) 5

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Need help with courseReplace 250 with 575 and -3 with -5.
Svetlanka [38]

Given

The demand function

p(x)=\frac{250}{\sqrt{x}}-5

To determine:

a) The revenue function.

b) The marginal revenue.

c) The marginal revenue when x=200.

d) The equation of tangent, and its derivation.

Explanation:

It is given that,

p(x)=\frac{250}{\sqrt{x}}-5

a) The revenue function is given by,

\begin{gathered} R(x)=x\cdot p(x) \\ R(x)=x\times(\frac{250}{\sqrt{x}}-5) \\ R(x)=250\sqrt{x}-5x \end{gathered}

b) The marginal revenue function is,

\begin{gathered} R^{\prime}(x)=\frac{d}{dx}(R(x)) \\ =\frac{d}{dx}(250\sqrt{x}-5x) \\ =250\times(\frac{1}{2}\times x^{-\frac{1}{2}})-5 \\ =\frac{125}{\sqrt{x}}-5 \end{gathered}

c) The marginal revenue when x=200 is,

\begin{gathered} R^{\prime}(200)=\frac{125}{\sqrt{200}}-5 \\ =\frac{125}{10\sqrt{2}}-5 \\ =8.8388-5 \\ =3.8388 \\ =3.84 \end{gathered}

Hence, the marginal revenue is 3.84.

d) Let y=mx+c is the tangent.

Then,

y=3.84x+c

That implies, for y=12.68, and x=200,

\begin{gathered} 12.68=3.84\times200+c \\ 12.68=768+c \\ c=12.68-768 \\ c=-755.32 \end{gathered}

Hence, the equation of tangent is,

y=3.84x-755.32

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2 years ago
Find the cost per roll if a bag of five lunch rolls is $2.50.
Andru [333]
<h3><u><em>My friends the answer is:</em></u></h3><h3><u><em>If 1 lunch =$2.50 </em></u></h3><h3><u><em> 2 lunches = $5.00 (2.50x2) </em></u></h3><h3><u><em> 3 lunches =$7.50 </em></u></h3><h3><u><em> 4 lunches =$10.00 </em></u></h3><h3><u><em> 5 lunches= $12.50 </em></u></h3><h3><u><em> Just add $2.50</em></u></h3>
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