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Assoli18 [71]
2 years ago
5

Y is what times X? No explanation please. Thank you.

Mathematics
2 answers:
Damm [24]2 years ago
7 0

Answer:

y= 1/4x

Step-by-step explanation:

Sonja [21]2 years ago
6 0

Answer:

0x4, 0x8

Step-by-step explanation:

You might be interested in
If this sample is representative of the student population of 360 students, about how many students in the school joined three c
kirill115 [55]

Answer:

For 1 club it is 120 students

Step-by-step explanation:

360/3=120

3 0
2 years ago
What’s are the answers for both?
nevsk [136]

Answer:

<h2>d = 8</h2><h2>g = 2</h2>

Step-by-step explanation:

8d + 4 = 5d + 28

Group like terms

That's

8d - 5d = 28 - 4

3d = 24

Divide both sides by 3

d = 8

\frac{7(7g + 8)}{4}  = 38.5

Cross multiply

we have

7(7g + 8) = 38.5(4)

49g + 56 = 154

49g = 154 - 56

49g = 98

Divide both sides by 49

g = 2

Hope this helps you

5 0
3 years ago
When 1 is subtracted from three- tenths of the number, the result is equal to one-fifth of a number. What is the number
Bas_tet [7]
Based on the given mathematical statement, it can be rewritten into a mathematical equation to simplify and to be solved easily. The statement, "When one is subtracted from three-tenths of a number" corresponds to the equation, 3x/10 - 1, that is assuming the number is represented by the variable x. This is equal to one-fifth of the number. In other words,
3x/10 - 1 = x/5
x = 10
8 0
2 years ago
Somebody help me with this please!!
Slav-nsk [51]

Notice the following pattern:

2 - 0 = 2

6 - 2  = 4

12 - 6 = 6

20 - 12 = 8

It's reasonable to assume that consecutive terms in the sequence differ by increasing multiples of 2, so that for the next number (call it x) we expect to see

x - 20 = 10  ==>  x = 30

and for the number after that (call it y) we would see

y - x = y - 30 = 12  ==>  y = 42

4 0
3 years ago
Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh
fredd [130]

With

\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k

we have

\mathrm d\vec r=(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

The vector field evaluated over this parameterization is

\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k

so the line integral is

\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

=\displaystyle\int_{-1}^1(16t+6t^2-12t^2)\,\mathrm dt=-4

6 0
2 years ago
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