Fr33 points 38/827. 72/727

How many pieces 3 and three fifths in. long can be cut from 28 metal rods each 15 in. long? Disregard waste.

Murrr4er [49]

Answer: 112 pieces

Step-by-step explanation:

1. Rewrite $3^{\frac{3}{5}}$ as a decimal. Divide the numerator and the denominator of the fractional part and add it to the integer part:

$3+0.6=3.6in$

2. You know that each metal rod is 15 inches long. Then, you must divide the lenght of each one by 3.6:

$pieces=\frac{15in}{3.6in}4.16$

3. The waste is 0.16, therefore, you obtain 4 pieces from a metal rod. The total pieces obtained from 28 metal rods are:

$total=4pieces*28=112pieces$

8 0

2 years ago

Read 2 more answers

PLEASE HELP ME!!!!!!! VERY CONFUSED AND I NEED THIS VERY BADLY!!!!!! I appreciate the help!!!!

maksim [4K]

Answer:

hey you forgot the picture this time bud

4 0

2 years ago

Adding, Subtracting, Multiplying, and Dividing Rationals and Solving Equations with Rationals in a real world scenario?

eduard

Answer:

cnc machining can include a lot of maths in it

4 0

3 years ago

The perimeter of a rectangle is 96cm its shortest side has a length of 5cm state the length of the longest side

Rainbow [258]

Answer:

43cm

Step-by-step explanation:

96-10 (5 x2 sides)=86

86/2 sides=43 longest side

4 0

2 years ago

2067 Supp Q.No. 2a Find the sum of all the natural numbers between 1 and 100 which are divisible by 5. Ans: 1050

Alborosie

5

Answer:

1050

Step-by-step explanation:

Natural Numbers are positive whole numbers. They aren't negative, decimals, fractions. We can just divide 5 into 100 to find how many natural numbers go up to 100 and just add them but that is just to much.

There is a easier method.

E.g: Natural Numbers that are divisible by a Nth Number. is the same as adding the Nth Numbers to a multiple of that Nth Term. For example, let say we need to find numbers divisible by 2. We know that 4 is divisible by 2 because 4/2=2. We can add the Nth numbers which is 2 to 4. 4+2=6. And 6 is divisible by 2 because 6/2=3. We can call this a arithmetic series. A series which has a pattern of adding a common difference

Back to the problem, we can use the sum of arithmetic series formula,

$y = x( \frac{z {}^{1} + {z}^{n} }{2} )$

Where x is the number of terms in our sequence. Z1 is the fist term of our series. ZN is our last term. And y is the sum of all of the terms

The first term is 5, the numbers of terms being added is 20 because 100/5=20. The last term is 100.

$y = 20( \frac{5 + 100}{2} )$

$y = 20( \frac{105}{2} )$

$y = 1050$

5 0

2 years ago