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3 years ago

I was out when my teacher told us this cause my dad died and she refused to help

Mathematics

2 answers:

STatiana [176]3 years ago

7 0

For number 14 it's 0.35 that the answer but do the calculator if u don't know how to do fraction do division because fraction are division remember that

vovikov84 [41]3 years ago

7 0

Hope this can help you with it

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What is the surface area of a sphere with a diameter of 12 centimeters? (Use 3.14 for π .)

tino4ka555 [31]

The answer is 452.39 centimeters

7 0

4 years ago

Kim finds a 1-meter tree branch and marks it off in thirds and fifths. She then breaks the branch along all the markings and rem

True [87]

Answer:

3/5

Step-by-step explanation:

We want to find the fraction of the original branch that remains, so we will assume a length of the branch in order to make our calculation easier.

Since Kim marks it off in thirds and fifths, let's find the least common multiple of 3 & 5.

Least common multiple of 3 & 5 is 15.

Thus,let's make the length of the branch to be 15-meter long.

Now, if the branch is 15 m long, considering the markings of thirds and fifths, the branch would be cut at:

3, 5, 6, 9, 10, 12 meters.

We are told that She then breaks the branch along all the markings and removes one piece of every distinct length. Thus;

Distinct lengths are;

3 metres

5 - 3 = 2 metres

10 - 9 = 1 meter

Total she removes = 3 + 2 + 1 = 6 meters.

Total remaining is;

15 - 6 = 9 meters

Expressing this as a fraction of the original branch gives:

9/15

Divide both numerator and denominator by 3 to get; 3/5

7 0

3 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

3 years ago

6) 9(x - 1)+ 4x<br><br>what's the answer

svet-max [94.6K]

Answer:

13x-9

Step-by-step explanation:

9×(x - 1)

9x - 9 +4x

collect like terms, 9x+4x=13x

4 0

3 years ago

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Suppose Martin is a very talented used-car salesman. Whenever Martin talks to a new customer, there is a 50% chance

Likurg_2 [28]

Answer:

50x20=N-2xy=z

Step-by-step explanation:

there is polominals substraction,addtion and

divided

sana po makatulong po sa inyo

8 0

3 years ago

Read 2 more answers