Answer: 540
Step-by-step explanation:
Given : The owner of a stereo store wants to advertise that he has many different sound systems in stock.
Number of different CD players =6
Number of different receivers= 10
Number of different speakers = 9
We are assuming that a sound system consists of one of each .
Then by Fundamental principle of counting , we have
The number of different sound systems can he advertise = (Number of different CD players)x (Number of different receivers) x(Number of different speakers)
= 6 x10 x 9 =540
Hence, the number of different sound systems can he advertise =540
<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,
0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
Answer:
26.5%
Step-by-step explanation:
All you have to do is subtract 64 - 37.5 which would get you to 26.5%. Hope this helps.
M=6/5 and n = sqrt(2), is rational (but not an integer) and n is irrational.
The case with n = sqrt(9)=3, is not a solution. The case with m=4pi neither.
The last case is m = 6/2=3, integer, so neither works.
So, it is the one with m=6/5 and sqrt(2)
