Put the negative exponent as the denominator in a fraction, so you'd get -7/1
Answer:
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.
This means that 
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

0.6236*100 = 62.36%
0.8964*100 = 89.64%
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Answer=24.49 I’m not 100% sure but I believe this is the answer :)
Hope it helps
Answer:
The screen is black? there is nothing there
Step-by-step explanation:
this is nonsense man
Answer:
Grade B score:
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73.3
Standard Deviation, σ = 9.7
We are given that the distribution of score on test is a bell shaped distribution that is a normal distribution.
Formula:

B: Scores below the top 5% and above the bottom 62%
We have to find the value of x such that the probability is 0.62
Calculation the value from standard normal z table, we have,
We have to find the value of x such that the probability is 0.05

Calculation the value from standard normal z table, we have,
Thus, the numerical value of score to achieve grade B is
