-(-6) in simplest form is +6 because a - times a - is a +
90/139 is the only fraction not equivalent to 45/70.
To find if a fractions are equivalent, divide the numerator by the denominator for each fraction.
45/70=0.642857
27/42=0.642857
9/14=0.642857
63/98=0.642857
Notice how all of these get you the same number. However, when you divide 90 by 137, you get 0.64748, which is not the same as the others. Therefore, 90/137 is the fraction that is not equivalent to 45/70.
Answer:
Step-by-step explanation:
Given that:
Population Mean = 7.1
sample size = 24
Sample mean = 7.3
Standard deviation = 1.0
Level of significance = 0.025
The null hypothesis:
The alternative hypothesis:
This test is right-tailed.
Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test 
The test statistics can be computed as:
t = 0.980
Decision rule:
Since the calculated value of t is lesser than, i.e t = 0.980 < , then we do not reject the null hypothesis.
Conclusion:
We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.
Answer:
This is not a real question rephrase
Step-by-step explanation:
"measures to the nearest tenth of a pound" tell us to round each of the weights listed to the nearest tenth (since the unit is already pounds, no conversion is needed). What this means is if the second number to the right of the decimal is 5 or greater, then we add 1 to the first number to the right of the decimal (and replace the second number with a zero). With all this said, it's much easier to show you, rather than to try to explain it. :D
4.35 is rounded up to 4.4 because the second number to the right of the decimal is 5.
Packet A = 4.4
Packet B = 4.4
Packet C = 4.5
Packed D = 4.4
The question is asking what the heaviest reading will be, so from the whole list above we pick the highest number which is 4.5 pounds. Notice how the answer is not Packet C, or 4.48 pounds, but 4.5 pounds. It is asking for the reading, not the packet, nor the weight. Hope this helps.
