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I am Lyosha [343]
3 years ago
9

Se van a transportar sacos que contienen 50 kg de azúcar cada uno, el camión que se va utilizar para el transporte de los sacos

tiene una capacidad de carga de 8 toneladas.
El peso del camión es de 2,000 kg, con la información determina lo siguiente:
Una función que te permita calcular la cantidad de sacos que puede transportar
Mathematics
1 answer:
LekaFEV [45]3 years ago
7 0

Function: 50x=8000 (maximum number of packages: 160)

Step-by-step explanation:

In this problem, we have:

C=8 ton = 8000 kg is the capacity of the truck (the amount of mass that can be stored in the truck)

p = 50 kg is the mass of each package that need to be stored in the truck

We can find the number of packages that can be transported as follows: calling this number x, the total mass of x packages is

p\cdot x

This amount should be at most equal to the capacity of the truck, therefore:

px=c

And substituting the numbers,

50x=8000

And solving the equation, we can found the number of packages that can fit into the truck:

x=\frac{8000}{50}=160

Learn more about equations:

brainly.com/question/11306893

brainly.com/question/10387593

#LearnwithBrainly

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April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how
Ostrovityanka [42]

40 adult tickets were sold and 35 children tickets were sold

<em><u>Solution:</u></em>

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 8

Cost of 1 children ticket = $ 5

<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>

Number of tickets sold = 75

number of adult tickets sold + number of children tickets sold = 75

a + c = 75 ----- eqn 1

<em><u>Given that April collected $495</u></em>

Thus we can frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495

a \times 8 + c \times 5 = 495

8a + 5c = 495 ----- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

From eqn 1,

a = 75 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8(75 - c) + 5c = 495

600 - 8c + 5c = 495

-3c = 495 - 600

-3c = - 105

<h3>c = 35</h3>

Substitute c = 35 in eqn 3

a = 75 - 35

<h3>a = 40</h3>

Thus 40 adult tickets were sold and 35 children tickets were sold

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