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2 years ago

PLEASEEEE HELP I NEED A ANSWER ASAP!!!!!!!

Mathematics

2 answers:

Licemer1 [7]2 years ago

8 0

Answer:

520 - 303.93 - (10.99 * 4) - 25.25 - 73.43x ≥ 0

1) Parentheses

520 - 303.93 - 43.96 - 25.25 - 73.43x ≥ 0

2) Combine like terms

146.86 - 73.43x ≥ 0

3) Get the variable term alone

-73.43x ≥ -146.86

4) Divide to solve

x ≤ 2

** dividing by a negative number, the inequality sign flips **

ANSWER :

x ≤ 2

lawyer [7]2 years ago

3 0

Step-by-step explanation:

303.93+(4×10.99 )+25.25+73.43x = 520

303.93 + 43.96 + 25.25 + 73.43x = 520

373.14 + 73.43x = 520

73.43x = 520 - 373.14

73.43x = 146.76

x = 146.76 ÷ 73.43

x = 2

x ≤ 2

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$17-2.262\frac{1.9}{\sqrt{10}}=15.641$

$17+2.262\frac{1.9}{\sqrt{10}}=18.359$

So on this case the 95% confidence interval would be given by (15.641;18.359)

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=17$ represent the sample mean

$\mu$ population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=10-1=9$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that $t_{\alpha/2}=2.262$