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2 years ago

Please help. quickly if possible

Mathematics

2 answers:

Mariulka [41]2 years ago

8 0

C

7x18 divided by 2 equals 63
18x22=396
63+396=459

Kay [80]2 years ago

3 0

Answer:

C 459cm2

Step-by-step explanation:

You multiply the area of the square first and add that to the area of the two right triangles.

Area of the square - Bh = 22(18) = 396

Area of ONE right triangle - 1/2bh h = 7 b = the base of the triangle

Look at the bottom of the square (18 cm) and divide that by two to get the base of the triangle

1/2(9)(7) = 31.5

Area of BOTH right triangles - 31.5(2) = 63

Total Area - Then you add 396 to 63 and you get 459 cm2, or C, which is the answer

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Write the point-slope form with two points ..of the given line that passes through the points (0, -3) and (4, 1). Identify (x1,

frez [133]

You need to find the slope too.
$m = \frac{y2 - y1}{x2 - x1} = \frac{ - 3 - 1}{0 - 4} = \frac{ - 4}{ - 4} = \frac{1}{1}$
point slope formula y - y1 = m(x - x1)
use (0, -3)
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2 years ago

When studying radioactive material, a nuclear engineer found that over 365 days,

Gnom [1K]

Answer:

a) The mean number of radioactive atoms that decay per day is 81.485.

b) 0% probability that on a given day, 50 radioactive atoms decayed.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\lambda$ is the mean in the given interval.

a. Find the mean number of radioactive atoms that decayed in a day.

29,742 atoms decayed during 365 days, which means that:

$\lambda = \frac{29742}{365} = 81.485$

The mean number of radioactive atoms that decay per day is 81.485.

b. Find the probability that on a given day, 50 radioactive atoms decayed.

This is P(X = 50). So

$P(X = 50) = \frac{e^{-81.485}*(81.485)^{50}}{(50)!} = 0$

0% probability that on a given day, 50 radioactive atoms decayed.

5 0

2 years ago

The area of a rectangular piece of paper is 32 square inches. The perimeter is 24 inches.

rodikova [14]

Answer

4 and 8

Explanation

List all factors of 32 and then find which number equals 24 when added

You could waste time and use alegbra lol

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2 years ago

Consider this sphere inside the cylinder. Which statements are true? Check all that apply. NEED HELP ASAP

-Dominant- [34]

Option A: The height of the cylinder is equal to the diameter of the sphere.

Option C: The radius of the sphere is half the height of the cylinder.

Option E: The volume of the sphere is two-thirds the volume of the cylinder.

Solution:

The sphere is inside the cylinder.

Let r be the radius of the sphere.

Option A: The height of the cylinder is equal to the diameter of the sphere.

The sphere is fully occupied the cylinder.

If we draw the vertical line through enter of the sphere, which is equal to the height of cylinder.That is h = d. It is true.

Option B: The height of the cylinder is two times the diameter of the sphere.

That is h = 2d. From the above option, we know that h = d.

So, it is not true.

Option C: The radius of the sphere is half the height of the cylinder.

we know that diameter = 2 × radius (d = 2r)

From option A, we have h = d.

Substitute d = 2r, we get

⇒ h = 2r

Divide by 2 on both sides, we get

$$\Rightarrow \frac{h}{2}=r$

Therefore, it is true.

Option D: The diameter of the sphere is equal to the radius of the cylinder.

It is not true, because diameters of both cylinder and sphere are equal.

Option E: The volume of the sphere is two-thirds the volume of the cylinder.

Radius of cylinder and sphere = r

Height of cylinder h = 2r (by option C)

Volume of cylinder = Volume of sphere

$$\Rightarrow \pi r^2 h = \frac{4}{3} \pi r^3$ (formula)

$$\Rightarrow \pi r^2 (2r) = \frac{2\times2}{3} \pi r^3$

$$\Rightarrow 2 \pi r^3= \frac{2}{3} \times 2\pi r^3$

Hence it is true.

Option A, option C and option E are true.

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