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3 years ago

Please i need this 1/3 x 1/3

Mathematics

2 answers:

OleMash [197]3 years ago

8 0

Answer: 1/3 x 1/3 = 1/9

Step-by-step explanation: have a nice day

Simora [160]3 years ago

4 0

It is 1/9 because one of her 1/3 * 1/3 is 1/9

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Help me please. im failing

Inessa05 [86]

Answer:

Area = 31.5 units^2

Step-by-step explanation:

7 x 3 = 21

Area of triangle is (height x base) / 2

(3 x 7) / 2 = 10.5

21 + 10.5 = 31.5

5 0

2 years ago

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The Foster Family, and the Tyson family, and the O'Jennie family, got together for Thanksgiving, and had a large turkey that cou

sasho [114]

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2 years ago

The position of an object moving along an x axis is given by x = 3.24 t - 4.20 t2 + 1.07 t3, where x is in meters and t in secon

Pavel [41]

Answer and explanation:

Given : The position of an object moving along an x axis is given by $x=3.24t-4.20t^2+1.07t^3$ where x is in meters and t in seconds.

To find : The position of the object at the following values of t :

a) At t= 1 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(1)=3.24(1)-4.20(1)^2+1.07(1)^3$

$x(1)=3.24-4.20+1.07$

$x(1)=0.11$

b) At t= 2 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(2)=3.24(2)-4.20(2)^2+1.07(2)^3$

$x(2)=6.48-16.8+8.56$

$x(2)=-1.76$

c) At t= 3 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(3)=3.24(3)-4.20(3)^2+1.07(3)^3$

$x(3)=9.72-37.8+28.89$

$x(3)=0.81$

d) At t= 4 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(4)=3.24(4)-4.20(4)^2+1.07(4)^3$

$x(4)=12.96-67.2+68.48$

$x(4)=14.24$

(e) What is the object's displacement between t = 0 and t = 4 s?

At t=0, x(0)=0

At t=4, x(4)=14.24

The displacement is given by,

$\triangle x=x(4)-x(0)$

$\triangle x=14.24-0$

$\triangle x=14.24$

(f) What is its average velocity from t = 2 s to t = 4 s?

At t=2, x(2)=-1.76

At t=4, x(4)=14.24

The average velocity is given by,

$\triangle x=x(4)-x(2)$

$\triangle x=14.24-(-1.76)$

$\triangle x=14.24+1.76$

$\triangle x=16$

4 0

3 years ago

c.) The sonar of a navy cruiser detects a submarine that is 4000 feet from the cruiser. The angle between the water line and the

Kamila [148]

Answer:

2236.77 feets

Step-by-step explanation:

From the attached picture, we are to find x, which is the vertical depth of the submarine.

Using trigonometry based on the illustration in the diagram:

Sinθ = opposite / hypotenus

Sinθ = x (depth of submarine) / distance from ship (4000)

Hence,

Sinθ = x / 4000

θ = 34°

Sin34 = x / 4000

0.5591929 * 4000 = x

2236.7716 = x

Hence, depth of submarine = 2236.77 feets

7 0

2 years ago

PLEASE HELP!!

FromTheMoon [43]

Step-by-step explanation:

Given

Model to Actual = 5:9

5cm in Model = 9cm actual

1cm in model = (9/5)cm = 1.8cm

36cm in model = 1.8cm x 36 = 64.8cm

3 0

2 years ago