Answer:
a. P= 0.6364
b. P = 0.3636
c. Q = $21.25
d. P = 0.5
Step-by-step explanation:
given data
value of a stock varies = $13 to $24
solution
P (stock value is more than $17)
P = 
P = 
P = 0.6364
and
P (value of the stock is between $17 and $21)
P = 
P = 
P = 0.3636
and
Let the upper quartile be Q


(24 - Q) = 2.75
so
Q = $21.25
and
P(X > 20 | X > 16)
P = 
P = 
P = 0.5
Answer: Saturday
Step-by-step explanation:
Saturday is at the highest point meaning it has less empty tables
The answer is C, you can tell because the b=-1, so that eliminates d, then you know the slope is positive because of the direction it goes, so that eliminates a. Then if you look at the slope, it goes up 3 over 1, so that makes the answer C.
Hope this helps
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
brainly.com/question/25970931
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Answer:
The range of data is 9
Step-by-step explanation:
We know that
range of data = maximum value of data - minimum value of data
Now, we can find maximum value of data
and minimum value of data
so,
maximum value of data =9
minimum value of data =0
now, we can plug these values
and we get
range of data =9-0
range of data =9