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Kruka [31]
2 years ago
11

Help please!!

Mathematics
2 answers:
Free_Kalibri [48]2 years ago
7 0
Tan²( θ ) - (1 + √3) tan (θ) + √3 = 0

tan²( θ ) - (tan (θ) + √3 tan (θ)) + √3 = 0

tan²( θ ) - tan (θ) - √3 tan (θ) + √3 = 0

tan( θ ) ( tan (θ) - 1) - √3 ( tan (θ) - 1 ) = 0

( tan( θ ) - 1 ) ( tan( θ ) - √3 ) = 0


tan( θ ) - 1 = 0

θ = π/₄

tan( θ ) - √3 = 0


θ = π/₃


so θ = π/₄ and θ = π/₃
irinina [24]2 years ago
7 0

Answer:

\huge \boxed{  \red{  \boxed{\begin{cases} \theta   =   {45}^{ \circ} \\    \theta=      {60}^{ \circ}  \end{cases} }}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • trigonometry
  • PEMDAS
<h3>let's solve:</h3>

distribute tan(θ):

=>tan²(θ)-(tan(θ)+√3tan(θ))+√3=0

remove parentheses:

=>tan²(θ)-tan(θ)-√3tan(θ)+√3=0

so this equation is now in standard form i.e ax²+bx+c=0

we can solve by factoring as we solve quadratic equation

factor out tanθ:

=>tan(θ)(tan(θ)-1)-√3tan(θ)+√3=0

factor out -√3:

=>tan(θ)(tan(θ)-1)-√3(tan(θ)-1)=0

group:

=>(tan(θ)-√3)(tan(θ)-1)=0

separate it as two different equation:

\implies  \begin{cases} \tan( \theta)  - 1 = 0 \\   \tan( \theta)  -  \sqrt{3} = 0  \end{cases}

add 1 and √3 to both sides to first and second equation respectively:

\implies  \begin{cases} \tan( \theta)  - 1 + 1 = 0 + 1 \\   \tan( \theta)  -  \sqrt{3} +  \sqrt{3}  = 0   +  \sqrt{3} \end{cases}

\implies  \begin{cases} \tan( \theta)   =  1 \\   \tan( \theta)  =     \sqrt{3} \end{cases}

\therefore  \begin{cases} \theta   =   {45}^{ \circ} \\    \theta=      {60}^{ \circ}  \end{cases}

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Define the function add_mn that takes two integers m, n as arguments and returns m + 10 * n. For instance, add_mn 3 5 = 3 + 10*5
jok3333 [9.3K]

Answer:

// C++ Program to arithmetic operationf on 2 Numbers using Recursion

// Comments are used for explanatory purpose

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using namespace std;

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8 0
3 years ago
Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS: A) cos E = 312 + 392 – 2(3
defon

This question is incomplete because the options were not properly written.

Complete Question

Which of the following applies the law of cosines correctly and could be solved to find m∠E? ANSWERS:

A) cos E = 31²+ 39² – 2(31)(39)

C) 56² = 39² – 2(39) ⋅ cos E

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Answer:

D) 56² = 31² + 39² – 2(31)(39) ⋅ cos E

Step-by-step explanation:

From the above diagram, we see are told to apply the law of cosines to solve for m∠E i.e Angle E

The formula for the Law of Cosines is given as:

c² = a² + b² − 2ab cos(C)

Because we have sides d , e and f and we are the look for m∠E the law of cosines would be:

e² = d² + f² - 2df cos (E)

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f = 31

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Therefore, from the above calculation and step by step calculation, the option that applies the law of cosines correctly and could be solved to find m∠E

Is option D: 56² = 31² + 39² – 2(31)(39) ⋅ cos E

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