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2 years ago

What is the solution to this equation?

Mathematics

1 answer:

Fantom [35]2 years ago

7 0

Answer:

x=-17

Step-by-step explanation:

Original Equation;

x+12=-5

The 12 will cross the equal sign so it will become -12. So it's going to be;

x=-5-12

There are two negative number so you add them and when you add them it would still be negative. And you would have to add them because when there are two negative numbers without any other sign you will have to add so it's going to be;

x=-17

This is the final answer!!!

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For the graph determine the domain and the range

Ira Lisetskai [31]

Domain: is x is equal to or more than-3, it is also equal to and less than 1.
Range: Y is equal to or greater than 2, it is also equal to and less than 5.

8 0

3 years ago

Question number 1: 5/8 (16b+24) -1/2b Question number 2: 3/4 (16/64 + 12a) -9a

Sophie [7]

Answer:

Problem 1. (19/2)b + 15

Problem 2. 3/16

Step-by-step explanation:

Question number 1

5/8 (16b+24) -1/2b =

= (5/8) * (16/1) * b + (5/8) * 24 - (1/2)b

= 10b + 15 - (1/2)b

= (20/2)b - (1/2)b + 15

= (19/2)b + 15

Question number 2

3/4 (16/64 + 12a) -9a =

= (3/4) * (16/64) + (3/4) * 12a - 9a

= (3 * 16)(4 * 64) + (3/4) * (12/1) * a - 9a

= (3 * 1)(4 * 4) + (3 * 12)/(4 * 1) * a - 9a

= 3/16 + (3 * 3)/(1 * 1) * a - 9a

= 3/16 + 9a - 9a

= 3/16

5 0

3 years ago

7) what is the BEST conclusion we can draw from the graph (the answers are in the picture)

Viktor [21]

Answer:

Step-by-step explanation:

7 0

3 years ago

Help me with 16,17,18,and 19 please simpl

mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

$\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\ \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\ \\=\dfrac{t^2-4t-3}{t^2+3t+18}$

Ques 17)

$\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\ \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}$

Ques 18)

Let the blank space be denoted by the quantity 'x'.

$\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2$

Ques 19)

Let the missing quantity be denoted by 'x'.

$\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9$

7 0

2 years ago

Marcus has two salary options for his new job.

Lady bird [3.3K]

Answer:

$125

Step-by-step explanation:

5 0

3 years ago