The equation is 12.5n where n stands for any hour that Phil is riding his bike. I'm using the nth term here though.
<span>((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX = (x^2 + 2x delta x + (delta x)^2 + x + delta x - x^2 - x) / delta x = delta x (2x + delta x + 1) / delta x = 2x + delta x + 1
Therefore, </span>Lim as x tends to 0 of <span>((x + delta X)^2 + x + deltaX - (x^2 + x)) / deltaX</span> = 1 + delta x
It depends on the size of each angle. If a parallelogram has the same sizes of the quadrilateral then they could both be congruent.
Hope this helps! :D
He can reach 2.6 meters or 260 centimeters
