Formula for standard deviation sample calculation is:
SD = sqrt (( ∑( x - m)²) / ( n - 1 )),
where x stays for each value in the data set, m stays for mean of all values in the data set, and n stays for the number of values in the data set.
For example: Find the sample standard deviation for the set of numbers: 10, 11, 11, 12, 12.
First we will find mean of all avlues: m = ( 10 + 11 + 11 + 12 +12 ) / 5 = 11.2
SD = sqrt (( 1.2² + 0.2² + 0.2² + 0.8² + 0.8² ) / ( 5 - 1 ))=
= sqrt ( 2.8 / 4 ) = √0.7 = 0.837
The question is asking for the lower bound of the 95% two tailed Confidence interval of the normally distributed population.
95% C.I. is given by 200 + or - 1.96(25) = 200 + or - 49 = (151, 249)
Therefore, the minimum weight of the middle 95% of players is 151 pounds.
Answer:
the dimensions of the most economical shed are height = 10 ft and side 5 ft
Step-by-step explanation:
Given data
volume = 250 cubic feet
base costs = $4 per square foot
material for the roof costs = $6 per square foot
material for the sides costs = $2.50 per square foot
to find out
the dimensions of the most economical shed
solution
let us consider length of side x and height is h
so we can say x²h = 250
and h = 250 / x²
now cost of material = cost of base + cost top + cost 4 side
cost = x²(4) + x²(6) + 4xh (2.5)
cost = 10 x² + 10xh
put here h = 250 / x²
cost = 10 x² + 10x (250/ x² )
cost = 10 x² + (2500/ x )
differentiate and we get
c' = 20 x - 2500 / x²
put c' = 0 solve x
20 x - 2500 / x² = 0
x = 5
so we say one side is 5 ft base
and height is h = 250 / x²
h = 250 / 5²
height = 10 ft
Answer: 51
Step-by-step explanation:
From the question, we are informed that there are 2601 students in a school and that the teacher want them to stand in rows and columns.
Since the number of the row and column are equal, thus will go thus:
Let the number of row and column be represented by y. Therefore,
y × y = 2601
y² = 2601
y = ✓2601
y = 51
Therefore the rows and columns must be 51 each.
