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Leona [35]
4 years ago
14

Please help me with math i need it soon

Mathematics
2 answers:
Bas_tet [7]4 years ago
8 0
Divide each price by the number of cubic yards it buys to find the cost per cubic yard.

A. $165/(3 yd³) = $55/yd³

B. $240/(4 yd³) = $60/yd³

C. $300/(6 yd³) = $50/yd³

D. $360/(8 yd³) = $45/yd³ . . . . . . . this is the best price per cubic yard.
AnnyKZ [126]4 years ago
6 0
Lets get started :)

We are told that Mrs. Thymes is buying mulch for her gardens.

Let us check the price for each option:

\boxed {Option \ A}
3 yd³ for $165
Divide 165 by 3, to find the price per cubic yard:
\frac{165}{3} = $55 per cubic yard

\boxed {Option \ B }
4 yd³ for $240
Do the same:
\frac{240}{4} = $60 per cubic yard

\boxed {Option \ C }
6 yd³ for $300
\frac{300}{6} = $50 per cubic yard

\boxed {Option \ D }
8 yd³ for $360
\frac{360}{8} = $45 per cubic yard

Therefore, we can see that 8 yd³ for $360 is the best price

\boxed {Your \ Answer \ will \ be \ Option \ D }
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Whats 24×5. (20pts)​
Fantom [35]

Answer:

120

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Sin5A/SinA-cos5A/cosA=4cos2A​
irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

\frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ LHS = \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}   \\  \\  =  \frac{ \sin5A \:\cos A -  \cos5A \:  \sin A}{\sin A \:\cos A }  \\  \\  =  \frac{ \sin(5A -A )}{\sin A \:\cos A}  \\  \\ =  \frac{ \sin 4A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =4\cos 2A \\  \\  = RHS \\  \\ thus \\  \\  \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ hence \: proved

5 0
3 years ago
1. Under absorption costing, how much fixed manufacturing overhead cost is included in the company's inventory at the end of las
Jobisdone [24]

Answer:

1.

$5,200 a fixed manufacturing overhead cost is included in the company's inventory at the end of last year.

2.

Income Statement is Prepared in an MS Excel File Attached With this answer Please find it.

Step-by-step explanation:

1.

Fixed Manufacturing Overhead = Total Fixed manufacturing Overhead x Units in ending inventory  / Units produced

Fixed Manufacturing Overhead = 65,000 x 20 / 250 = $5,200

2.

File Attached.

There is a Difference of $5,200 in net operating income between the two costing methods. The amount of fixed asset assigned to closing inventory.

Download xlsx
3 0
3 years ago
Solve the equation -2 = 3x/5 + 1
kirill [66]

- 2 =  \dfrac{3x}{5}  + 1 | \times 5 \\  - 10 = 3x + 5 \\  - 3x = 15 | \div ( - 3) \\ x =  - 5

4 0
3 years ago
Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5
Setler79 [48]

Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\boxed{ \mathsf{ \red{y - y_{1} =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})  }}}

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\mathsf{\implies y - ( - 1.5) =  \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\mathsf{\implies (y  +  1.5) =  \frac{0  +  1.5}{2.5  } (x  )}

\mathsf{\implies y  +  1.5 =  \frac{ 1.5}{2.5  } x  }

\mathsf{\implies y  +  1.5 =  \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x  }

\mathsf{\implies y  +  1.5 =  \frac{ 3}{5 } x  }

multiplying both sides by 5

\mathsf{5y + 7.5 = 3x}

okay so this is the required equation of the dotted line

now we'll find the inequality

for this check whether the origin (0,0) lies under the shaded region or not

in this case it does

so

replacing x and y with 0

\mathsf{\implies5(0) + 7.5 = 3(0)}

\mathsf{\implies0 + 7.5 = 0}

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\mathsf{\implies7.5 > 0}

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\mathsf{5y + 7.5 > 3x}

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

<h3>y > 0.6x - 1.5 </h3>

that is the last option

5 0
3 years ago
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