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Answer:
See below. The answer is incomplete, I couldn't post it.
Step-by-step explanation:
Considering a function 
, it is said to be discontinuous when it has a hole or breaks, it means places where 
cannot be evaluated. For example, when the denominator equals to 0, it is not defined.
The equation 5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0 is a quadratic equation
The value of x is 8 or 1
<h3>How to determine the value of x?</h3>
The equation is given as:
5/2 - x + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0
Rewrite as:
-5/x - 2 + x - 5/x + 2 + 3x + 8/x^2 - 4 = 0
Take the LCM
[-5(x + 2) + (x -5)(x- 2)]\[x^2 - 4 + [3x + 8]/[x^2 - 4] = 0
Expand
[-5x - 10 + x^2 - 7x + 10]/[x^2 - 4] + [3x + 8]/[x^2 - 4] = 0
Evaluate the like terms
[x^2 - 12x]/[x^2 - 4] + [3x + 8]/[x^2 - 4 = 0
Multiply through by x^2 - 4
x^2 - 12x+ 3x + 8 = 0
Evaluate the like terms
x^2 -9x + 8 = 0
Expand
x^2 -x - 8x + 8 = 0
Factorize
x(x -1) - 8(x - 1) = 0
Factor out x - 1
(x -8)(x - 1) = 0
Solve for x
x = 8 or x = 1
Hence, the value of x is 8 or 1
Read more about equations at:
brainly.com/question/2972832
Answer:
You need to solve for Y. There should only be one corresponding y-value for that x-value. y = x + 1 is a function because Y is ALWAYS greater then X.
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
texas industries probably most affected most by agriculture
