All categories

2 years ago

18. The temperature was

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

6 0

Answer:

Step-by-step explanation: Find the number between 40 and -10.

start at 40 and end at -10.

-40=0

0-10=-10

the tempature changed by 50 degrees.

You might be interested in

John has a job selling souvenirs on a football stadium. He earns $10 per game plus $0.25 dollars for each souvenir he sells. How

Ahat [919]

Answer:

He needs to sell 100 souvenirs

Step-by-step explanation:

We want to know the number of souveniers John has to sell

Let the number of souveniers he sold at the game be s

At a rate of $0.25 per souvenier, the amount earned on souveniers for s souveniers will be:

$0.25 \times s =0.25s$

Now, if we added this to the amount he earns per game, we will have the total $35 earned for working at one game.

Thus, mathematically:

$0.25s + 10 = 35 \\ 0.25s = 35 - 10 \\ 0.25s = 25 \\ s = \frac{25}{0.25} \\ s = 100$

7 0

3 years ago

Find the sum \[\sum_{k = 1}^{2004} \frac{1}{1 + \tan^2 (\frac{k \pi}{2 \cdot 2005})}.\]

vampirchik [111]

Answer:1002

Step-by-step explanation:

$\Rightarrow \sum_{k=1}^{2004}\left ( \frac{1}{1+\tan ^2\left ( \frac{k\pi }{2\cdot 2005}\right )}\right )$

and $1+\tan ^2\theta =\sec^2\theta$

and $\cos \theta =\frac{1}{\sec \theta }$

$\Rightarrow \sum_{k=1}^{2004}\left ( \cos^2\frac{k\pi }{2\cdot 2005}\right )$

as $\cos ^2\theta =\cos ^2(\pi -\theta )$

Applying this we get

$\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]$

every $\theta$ there exist $\pi -\theta$

such that $\sin^2\theta +\cos^2\theta =1$

therefore

$\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]=1002$

6 0

3 years ago

The weekly demand for an item in a retail store follows a uniform distribution over the range 70 to 83. What would be the weekly

Xelga [282]

Answer:

Weekly demand will be 76.5

Step-by-step explanation:

Let X denote the weekly demand for an item

We have given that X follows a uniform distribution with a = 70 and b = 83

So $f(X)=\frac{1}{83-70}=\frac{1}{13}$

Now we need to find $x_0$ such that $P(X\leq x_0)=0.5$

$\oint_{70}^{x_0}f(x)dx=0.5$

$\oint_{70}^{x_0}\frac{1}{13}dx=0.5$

$\frac{x_0-70}{13}=0.5$

$x_0=76.5$

So weekly demand will be 76.5

6 0

3 years ago

on a map 2 inches represent 60 miles if a line between two cities measures 9 inches, how many miles apart are they?

DiKsa [7]

Answer:

270 miles.

Step-by-step explanation:

2 inches/60= 30 miles per inch. 9 inches times 30 = 270.

5 0

3 years ago

2 3 y−3+ 3 5 zstart fraction, 3, divided by, 2, end fraction, y, minus, 3, plus, start fraction, 5, divided by, 3, end fract

DanielleElmas [232]

Answer:

Step-by-step explanation:

1) This expression can be solved simply by plugging in the given conditions y=6 and z=3.

$\frac{3}{2}y-3+\frac{5}{3}z\:When\: y=6\:z=3 \Rightarrow \\\frac{3}{2}*(6)-3+\frac{5}{3}*(3) \Rightarrow 9-3+5=11$

8 0

3 years ago