The two enclosures will need three equal fences coming out from the wall and meeting another fence running parallel to the wall. If the fences coming out from the wall are x metres long the parallel fence will be (132 - 3x) metres long.
The area A = x(132 - 3x) = 132x - 3x^2
The derivative of A = zero when 132 - 6x = 0 which means the maximum area is when x = 22m
The maximum area = 22 x (132 - 3 x 22) = 1452 m^2
If you don’t know how to find derivatives then you could sketch the graph of y = x(132 - 3x).
This is an inverted parabola (hill) with x intercepts at 0 and 132/3 = 44.
The maximum point (top of the hill) is halfway between 0 and 44 I.e. 22m
Try any other value for x and the area will be smaller.
Answer:
I would say 5 kg because you get more kg with a little bit more money added
Answer:
140,120
Step-by-step explanation:
sum of angles in a quadrilateral =360
sum of the 1st two angles=60+40=100
360-100=260
the ratio of the remaining angles 7:6
therefore:
=140
for the second angle
260-140=120
Answer: R = {0, -3, -9, 5, 7}
Explanation: The range is the set of all y-coordinates for our ordered pairs.
So the range for this relation is {0, -3, -9, 5, 7}.
Answer:
The answer is 15.
Step-by-step explanation:
10% of 150 is 15. (you can take away the zero)
