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Tanzania [10]
3 years ago
7

Pls help. I need a scatterplot for this representation.

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0
1 2 3 4yyggggggggggghbrbhrheje
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SOMEONE PLEASE HELP ME.Mason spends $24 on hotdogs and buns for his graduation picnic. Hotdogs cost three dollars per pack and b
horrorfan [7]
So if he spends 24 spends 24 on the x and y they would be the Same
6 0
3 years ago
What number is 15% of 60
zhannawk [14.2K]

0.15 * 60 = 9 or 15/100 * 60/1 = 900/100 = 9

3 0
3 years ago
Read 2 more answers
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
Simplify 4+(9×2)÷(4-2)+1
kogti [31]

First we have to work out everything inside the parentheses (according to PEMDAS):

9 × 2 = 18

4 - 2 = 2

Now, we can rewrite the expression:

4 + 18 ÷ 2 + 1

According to PEMDAS, we should complete the division in the middle first:

18 ÷ 2 = 9

Now we can rewrite the expression again:

4 + 9 + 1

And now it's as simple as just adding the three numbers together:

4 + 9 + 1 = 14


Your final answer is 14. :)

3 0
3 years ago
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The volume of a rectangular prism, in cubic meters, is given by the expression x to the 3rd power
nydimaria [60]

Answer:

power of 3

Step-by-step explanation:

that formula of rectangular prism V=L×b×h when all of number are in meter will not convert if the number of cubic are not all meter must convet to be in meter by dividing by 10, 100 or 1000

5 0
2 years ago
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