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3 years ago

12.1 x 3 and a half. pls explain if possible

Mathematics

1 answer:

wariber [46]3 years ago

7 0

Answer:

Step-by-step explanation:

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Use words to write a comparison statement for the problem above.

pantera1 [17]

Looking at the question we can see that it says:

$41253>35214$

We should know what these symbols mean:

stands for something less than the other, for example:

We can say that 2 is less than 5 so in a symbolic form it can be written as,

$2$

Similarly,

$>$ stands for something greater than the other, for example:

We can say that 7 is greater than 5, in a symbolic form it can be written as,

$7>5$

So here, $42153>35214$ means that, 42153 is greater than 35214.

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3 years ago

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adell [148]

850/630= 1.35 exchange rate

150x1.35= 202.50

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4 years ago

Rise over run value?

finlep [7]

Is that all the information given?

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4 years ago

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Please help someone

uysha [10]

Answer:

Step-by-step explanation:

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3 years ago

The square of X varies inversely as the square root of Y and directly as the variable M. When M = 27 and Y = 16, then X = 9. Fin

irakobra [83]

Answer:

$Y = 441$

Step-by-step explanation:

Given

M = 27 when Y = 16 and X = 9

Required

Find Y when M = 7 and X = 2

We start by getting the algebraic representation of the given statement

$X^2 \alpha \frac{1}{\sqrt Y} \alpha M$

Convert the variation to an equation; we have

$X^2 = \frac{KM}{\sqrt Y}$

<em>Where K is the constant of variation;</em>

When M = 27; Y = 16; X = 9, the expression becomes

$9^2 = \frac{K * 27}{\sqrt{16}}$

This gives

$81 = \frac{k * 27}{4}$

Make K the subject of formula

$K = \frac{81* 4}{27}$

$K = \frac{324}{27}$

$K = 12$

Solving for Y when M = 7 and X = 2

Recall that $X^2 = \frac{KM}{\sqrt Y}$

Substitute values for K, M and X

$2^2 = \frac{12 * 7}{\sqrt{Y}}$

$4 = \frac{84}{\sqrt{Y}}$

Take square of both sides

$4^2 = (\frac{84}{\sqrt{Y}})^2$

$16 = \frac{7056}{Y}$

Make Y the subject of formula

$Y = \frac{7056}{16}$

$Y = 441$

3 0

3 years ago