Answer:
"Option 1: To the end of an array." is the correct answer.
Explanation:
The word "Append" means adding to the end of a document.
Appending means whatever new content is added, it is added at the end of the document or data structure.
Similarly,
Appending an array means adding new elements to the end of the array.
Hence,
"Option 1: To the end of an array." is the correct answer.
Answer:
electronic processing device
Answer:
C. Offset.
Explanation:
An offset operator can be defined as an integer that typically illustrates or represents the distance in bytes, ranging from the beginning of an object to the given point (segment) of the same object within the same data structure or array. Also, the distance in an offset operator is only valid when all the elements present in the object are having the same size, which is mainly measured in bytes.
Hence, the offset operator returns the distance in bytes, of a label from the beginning of its enclosing segment, added to the segment register.
For instance, assuming the object Z is an array of characters or data structure containing the following elements "efghij" the fifth element containing the character "i" is said to have an offset of four (4) from the beginning (start) of Z.
Answer:
#include <iostream>
using namespace std;
void divide(int numerator, int denominator, int *quotient, int *remainder)
{
*quotient = (int)(numerator / denominator);
*remainder = numerator % denominator;
}
int main()
{
int num = 42, den = 5, quotient=0, remainder=0;
divide(num, den, "ient, &remainder);
return 0;
}
Explanation:
The exercise is for "Call by pointers". This technique is particularly useful when a variable needs to be changed by a function. In our case, the quotient and the remainder. The '&' is passing by address. Since the function is calling a pointer. We need to pass an address. This way, the function will alter the value at the address.
To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.
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