Answer:
A, C
Step-by-step explanation:
Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.
Examining
A) True

Double angle 
B) False,
No further development towards a Trig Identity
C) True
Double Angle Sine Formula 

D) False No further development towards a Trig Identity
![[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)](https://tex.z-dn.net/?f=%5Bsin%28x%29-cos%28x%29%5D%5E%7B2%7D%20%3D1%2Bsin%282x%29%5C%5C%20sin%5E%7B2%7D%20%28x%29-2sin%28x%29cos%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B2sinxcosx%5C%5C%20%5C%5Csin%5E%7B2%7D%20%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B4sin%28x%29cos%28x%29)
Initially started 20 feet from the ground .
Went uphill 83 feet.
So: 20 + 83 = 103. The coaster is 103 ft above at this point.
Went down 42 feet
So: 103 - 42 = 61.
Went up 128 feet
So: 61 + 128 = 189
Finally, went down 90 feet
So: 189 - 90 = 99
99 ft above ground.
Since your scale is 1ft:1.26cm, a 30-ft tall school would need to have a

cm model. Dividing this by how tall each toothpick is, you'll get:
ANSWER: The model would be 6 toothpicks tall.
To find out how many cotton swabs you'll need, we just divide 37.8 by how tall each swab is:
ANSWER: The model would be 5 cotton swabs tall.
Answer:
ok so here is the answer: n
hk
b
a
х
V
Angle a = 126. What is the measure of angle b? Explain how you calculated your answer.
Angle a = 126 Write an equation(s) in terms of b to find the measure of angle h.
Calculate the measure of angle h, using the equation(s) you wrote for Part B.
How would knowing the measure of angle y change the equation(s) you wrote in Part B to find the measure of angle h?
2021 Muminate Education Inc Your input: factor x2+4x+3.
To factor the quadratic function x2+4x+3, we should solve the corresponding quadratic equation x2+4x+3=0.
Indeed, if x1 and x2 are the roots of the quadratic equation ax2+bx+c=0, then ax2+bx+c=a(x−x1)(x−x2).
Solve the quadratic equation x2+4x+3=0.
The roots are x1=−1, x2=−3 (use the quadratic equation calculator to see the steps).
Therefore, x2+4x+3=1(x+1)(x+3).
(x2+4x+3)=1(x+1)(x+3)
Step-by-step explanation: