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Harlamova29_29 [7]
3 years ago
7

D. 11=% 9 Express the following percent as fractions and decimals

Mathematics
1 answer:
padilas [110]3 years ago
5 0

Answer:

11_100

0.11

iam not sure

best of luck

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What is an equation of a line in point slope form that passes through the points (7,-8) and (-4,6)?
maw [93]

y=kx+b

for (7,-8): -8=7k+b. (function 1)

for (-4,6): 6=-4k+b (function 2)

Use function 2 - function 1

we get: 14=-11k

k=-14/11------>slope is -14/11

Now we know that first two options are wrong since they have the wrong slope for the function.

Plus -14/11 back to function 1/ or 2. Both are correct and can give you the answer. In this case I would plug it back to function 2.

6=14*4/11+b

b=66/11-56/11

b=10/11

We get y=-14/11x+10/11

subtract both side by 6.

y-6=-14/11x+10/11-66/11

y-6=-14/11x-56/11

y-6=-14/11(x+4)

So C is correct

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3 years ago
OA. 29 feet<br> OB. 19 feet<br> OC. 6 feet<br> OD. 36 feet
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What’s the question????
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3 years ago
Please help me! I will make you the brainliest! Don't answer if you don't know
Helen [10]
Table C is a function, because none of the numbers in the X column repeat. (All the other ones do.):-)Hope I could help!!
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All the number sets that apply to -4/5
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3 years ago
There are 20 machines in a factory. 7 of the machines are defective.
adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

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3 years ago
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