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KatRina [158]
3 years ago
11

the ages of three men are in the ratio 3:4:5.if the difference between the age of the oldest and the youngest is 18years, fine d

the sum of the age of the three men
Mathematics
1 answer:
hram777 [196]3 years ago
3 0

Answer:

108

Step-by-step explanation:

Givens

  • let the oldest one = 5x
  • Let the youngest one = 3x
  • Let the middle one = 4x

Equation

  • 3x + 18 = 5x  

Solution

  • 3x + 18 = 5x                         Subtract 3x from both sides
  • 3x - 3x + 18 = 5x - 3x          Combine
  • 18 = 2x                                 Divide by 2
  • 18/2 = 2x/2                          Divide
  • x = 9

Answer

  • 3x = 3*9 = 27
  • 5x = 5*9 = 45
  • 4x = 4*9 = 36
  • The sum is 108

Comment

This is a very tricky problem. It is not the usual way that 3 part ratios are handled. Thanks for posting.

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Answer:

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Step-by-step explanation:

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8 0
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AnnZ [28]

Answer:  \bold{A)\quad y=5sin\bigg(\dfrac{6}{5}x-\pi\bigg)-4}

<u>Step-by-step explanation:</u>

The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B

In the given function, B=\dfrac{6}{5}  →   P=2\pi \cdot \dfrac{5}{6}=\dfrac{10\pi}{3}

Half of that period is: \dfrac{1}{2}\cdot \dfrac{10\pi}{3}=\large\boxed{\dfrac{5\pi}{3}}

Calculate the period for each of the options to find a match:

A)\quad B=\dfrac{6}{5}:\quad 2\pi \div \dfrac{6}{5}=2\pi \cdot \dfrac{5}{6}=\dfrac{5\pi}{3}\quad \leftarrow\text{THIS WORKS!}\\\\\\B)\quad B=\dfrac{6}{10}:\quad 2\pi \div \dfrac{6}{10}=2\pi \cdot \dfrac{10}{6}=\dfrac{10\pi}{3}\\\\\\C)\quad B=\dfrac{5}{6}:\quad 2\pi \div \dfrac{5}{6}=2\pi \cdot \dfrac{6}{5}=\dfrac{12\pi}{5}\\\\\\D)\quad B=\dfrac{3}{10}:\quad 2\pi \div \dfrac{3}{10}=2\pi \cdot \dfrac{10}{3}=\dfrac{20\pi}{3}

7 0
3 years ago
3(x-1) help dawg please mate help me mates
lubasha [3.4K]

Answer: 1

Step-by-step explanation:

3(x-1)

3 times x = 3x

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3x-3

1

5 0
2 years ago
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Tcecarenko [31]

Answer:

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Step-by-step explanation:

-6x-8

-8x+9

-14x+1

4 0
3 years ago
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