or
Answer:
Solution given:
y=2x²-5x+6.....[1]
y=3x+3.........….[2]
solving equation 1&2
2x²-5x+6=3x+3
2x²-5x-3x+6-3=0
2x²-8x+3=0
comparing above equation with ax²+bx+c=0 we get
a=2
b=-8
c=3
by using quadratic equation
taking positive
taking negative
How can i answered this
2 answers:
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Answer:
q = 2
Step-by-step explanation:
0.5-0.125q=(q-1)/4
At first, we have to multiply both the sides by 4.
4 × (0.5 - 0.125q) = q - 1
or, 2 - 0.5q = q - 1
now, we change the side by taking constant into the right side and the number into the left side.
2 + 1 = q + 0.5q
or, 3 = q (1 + 0.5)
or, 3 = 1.5 q
or, 1.5 q = 3
or, = (3 ÷ 1.5) [Dividing both the sides by 1.5]
or, q = 2
Therefore, q = 2
Answer:
(c) 43.
Step-by-step explanation:
Given:
Margin of error (E) = 2
Sample variance = 44
Confidence level = 95%
The z- value at 95% confidence level is 1.96.
The sample using the provided information can be calculated as:
Hence, the correct option is (c) 43.