1. Y=1
2.Y=6
3.Y=3
4.Y=5
Explanation:
In The first one our x values are
-2 -1 0 1 2 3
And our y values are
-2 -1 0 1 2 3
3 6
This one is easy cause you can see that it’s counting by 1. For example it goes 3, 4, 5, 6, 7, 8.
THE SECOND ONE
the table is
-1 0 1 2 3 4
4 16
Our y values are 4 and 16
Subtract 16 - 4
divided by 2
12 divided by 2 is 6.
4 + 6 = 10
10 + 6 = 16
So it checks out.
To find the numbers after 4, just subtract 4 from 6 and then subtract 6 from the answer you get.
THE THRID ONE
The table is
0 1 2 3 4 5
-1 8 14
14 - 8 = 6
6 divided by 2 is 3
-1 + 3 = 2
2 + 3 = 5
5 + 3 = 8
8 + 3 = 11
11 + 3 = 14 ✔️
So this works
THE FOURTH ONE
the table is
6 7 8 9 10 11
32 47 57
47 - 57 = 10
10 divided by 2 is 5
So let’s try it
32 + 5 = 37
37 + 5 = 42
42 + 5 = 47
47 + 5 = 52
52 + 5 = 57 ✔️
So this works
For 1.30 you will shade in one full grid because that equals 1 and also shade in 3 coloms on the next grid which equals .30.
Then shade in 5 coloms and 1 single block on the the next grid which will equal .51 after
1/2a - 7 + 1/2 a = 1/3
1/2a + 1/2a = 1/3 + 7
2/2a = 22/3
a = 22/3
220 x 440 = 96800
96800/1000=96.8
but you can't have .8 of a bag so round in up to 97 bags
I hope this helps!
Because all outcomes are equally weighted, the probability you are looking for is given by :-
Number of favorable eventsTotal number of events
Number of favorable events
Total number of events
In your case: 6 or Even outcome={2,4,6}
6
or Even outcome
=
{
2
,
4
,
6
}
and Outcomes={1,2,3,4,5,6}
Outcomes
=
{
1
,
2
,
3
,
4
,
5
,
6
}
Hence:
Number of favourable eventsTotal number of events=36=12
