Answer:
by adding a transverse line to it interesting both of them
That's pretty expensive its usually cheaper. I would look for another gym. This isn't really a question though.
Step-by-step answer:
assuming the true-false test have equal probabilities (each 0.5), we can use the binomial probability to calculate the sum of probabilities of getting 10, 11 or 12 questions correctly out of 12.
p=probability of success = 0.5
N=number of questions
x = number of correct answers
then
P(x) = C(N,x)(p^x)((1-p)^(N-x))
where C(N,x) = N!/(x!(N-x)!) = number of combinations of taking x objects out of N.
P(10) = C(12,10)(0.5^10)((1-0.5)^2) = 33/2048 = 0.01611
P(11) = C(12,11)(0.5^11)((1-0.5)^1) = 3/1024 = 0.00293
P(12) = C(12,12)(0.5^12)((1-0.5)^0) = 1/4096 = 0.00024
for a total probability of 79/4096 = 0.01929
<span><span>=<span>(<span>10<span>x2</span></span>)</span>+<span>(<span>14x</span>)</span>+<span>(<span>5x</span>)</span>+<span>(7)</span>=</span><span>=<span>(<span>10<span>x2</span></span>)</span>+<span>(<span>14x</span>)</span>+<span>(<span>5x</span>)</span>+<span>(7)</span>=</span></span>
<span><span>=10<span>x2</span>+19x+7</span><span>=10<span>x2</span>+19x+7</span></span>.
<span>Answer: <span><span>(<span>2x+1</span>)</span><span>(<span>5x+7</span>)</span>=10<span>x2</span>+19x+<span>7</span></span></span>
