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3 years ago

John bought a new car for $22,000. He kept track of the value of the car

Mathematics

2 answers:

sasho [114]3 years ago

3 0

Answer:

what is the options

Step-by-step explanation:

Serggg [28]3 years ago

3 0

Answer:

Y=2,000(1+2.5)^12

Step-by-step explanation:

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Given that the series kcoskt kº +2 k=1 converges, suppose that the 3rd partial sum of the series is used to estimate the sum of

3241004551 [841]

Answer:

Step-by-step explanation:

Given that:

$\sum \limits ^{\infty}_{k=1} \dfrac{kcos (k\pi)}{k^3+2}$

since cos (kπ) = $-1^k$

Then, the series can be expressed as:

$\sum \limits ^{\infty}_{k=1} \dfrac{(-1)^kk)}{k^3+2}$

In the sum of an alternating series, the best bound on the remainder for the approximation is related to its $(n+1)^{th$ term.

∴

$\sum \limits ^{\infty}_{k=1} \dfrac{(-1)^{(3+1)}(3+1))}{(3+1)^3+2}$

$\sum \limits ^{\infty}_{k=1} \dfrac{(-1)^{(4)}(4))}{(4)^3+2}$

$= \dfrac{4}{64+2}$

$=\dfrac{2}{33}$

5 0

2 years ago

Fogoh!! Plz HELPi suck at math haha

quester [9]

Answer:

f(g(h(x))) = (sqrt(x) - 1)^4 + 4

Step-by-step explanation:

f(x) = x^4 + 4

g(x) = x - 1

h(x) = sqrt(x)

g(h(x)) = sqrt(x) - 1

f(g(h(x))) = (sqrt(x) - 1)^4 + 4

6 0

3 years ago

2.The number of tickets sold to a play for each showing is 78, 84, 87, 80, 91, 95, and 80.

Luden [163]

Answer:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

Step-by-step explanation:

We have the following data given:

78, 84, 87, 80, 91, 95, and 80.

The first step is order the dataset on increasing way and we got:

78, 80,80, 84,87, 91, 95

We can begin finding the minimum value and for this case is:

$Min =78$

The maximum is :

$Max = 95$

Now we can calculate the median since the sample size os n =7 the median would be the middle value at the position 4 from the dataset ordered and we got:

$Median =84$

Now we can find the quartile 1 we analyze the first 4 values 78, 80,80, 84 and the first quartile would be:

$Q_1= \frac{80+80}{2}= 80$

Now we can find the quartile 3 we analyze the last 4 values 84,87, 91, 95 and the third quartile would be:

$Q_3= \frac{87+91}{2}=89$

And finally the 5 number summary would be:

$Min = 78, Q_1 = 80, Median=84, Q_3 = 89, Max=96$

5 0

3 years ago

A water sprinkler has a range of 5 meters as shown. The jet of water from the sprinkler sweeps out at an angle of 85° as the noz

telo118 [61]

I found the image that accompanied this problem.
We need to solve for the area of the sector.

A = n/360 * π * r²
A = 85/360 * 3.14 * 5²
A = 0.2361 * 3.14 * 25
A = 18.5347

Answer is C. 18.5 square meters.

6 0

3 years ago

Read 2 more answers

Find the equation of the line passing through the point (–1, 5) and perpendicular to the line y = – 3x + 4.

dsp73

9514 1404 393

Answer:

A) 3y = x + 16

Step-by-step explanation:

The equation of a perpendicular line can be found by swapping the x- and y-coefficients and negating one of them. The constant will be chosen to match the given point.

Swapping coefficients, we get ...

-3y = x + c

Negating the y-coefficient gives ...

3y = x + c

Filling in the given point, we have ...

3(5) = -1 + c

16 = c

The equation of the perpendicular line can be written as ...

3y = x + 16 . . . . matches choice A

_____

Note that choice A is the only equation that gives a line with positive slope. The given equation has negative slope, so its perpendicular must have positive slope.

3 0

2 years ago