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TEA [102]
3 years ago
13

Is (-3, -9) a solution of the equation y = 3x ?

Mathematics
1 answer:
makkiz [27]3 years ago
3 0

Answer:

Yes.

Step-by-step explanation:

-3 * 3 = -9

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Use the laws of Sines and law of cosines to find missing dimensions​
Andrei [34K]

Answer:

A) ERROR

B) ∠C = 26°

Step-by-step explanation:

Houston, We have a problem!!! too much information

If we had a legit triangle, the law of sines would hold

19/sin138 = 8/sin20

  28.395 = 23.390

as this is NOT an equality, the triangle does not exist as described.

IF it did, we'd get different results depending on which set we used

∠F = 180 - 138 - 20 = 22°

Law of sines

19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>

or

8/sin20 =  DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>

If we attempt to use Law of cosines

DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>

so really none is correct because we attempt to use trig calculations to a non-triangle.

12) AC² = 15² + 19² - 2(15)(19)cos120

      AC = 29.51270...

29.51270 / sin120 = 15/sinC

C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>

6 0
3 years ago
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The​ _____ _____, denoted ModifyingAbove p with caretp​, is given by the formula ModifyingAbove p with caretpequals=​_____, wher
Vlada [557]

Answer:

The​ <u>sample proportion</u>, denoted by  ^p​, is given by the formula ^p=​ \frac{x}{n}, where x is the number of individuals with a specified characteristic in a sample of n individuals.

Step-by-step explanation:

Sample proportion is used to determine sample mean, sample standard error and test the hypotheses about the population.

<em>sample mean</em> can be stated as p and <em>sample standard error</em> can be found using the equation\sqrt{\frac{p*(1-p)}{n} } where

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And if n×p×(1-p)≥10, then sample is assumed large enough to assume normal distribution and apply statistical test.

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iVinArrow [24]

Answer:

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Step-by-step explanation:

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3 years ago
What is the square root of 234
zvonat [6]
The square root of 234 is 15.2970585408
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Please help me <br> Which one do I choose for each one
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For the first one i would choose the second answer, Not both.
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