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Bad White [126]
3 years ago
15

See attached picture ​

Mathematics
1 answer:
lions [1.4K]3 years ago
4 0

Answer:

ok i see it

Step-by-step explanation:

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PLEASE HELP! <br><br> will give brainlist
topjm [15]

Answer:

m∆T=44°

Step-by-step explanation:

> 180-108+28

> 180-136

> 44

3 0
3 years ago
Will mark the brainliest
Ivan

Answer:

C.

X = -5

Step-by-step explanation:

3 0
3 years ago
Solve the inequality 15 ≥ q + 3
oksano4ka [1.4K]

Answer:

q\le \:12

Step-by-step explanation:

<u>Solving</u>

\mathrm{Switch\:sides}  (Not a required step)

q+3\le \:15

\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}

q+3-3\le \:15-3\\=q\le \:12

\bold{q\le \:12}

<u>Graphing</u>

5 0
2 years ago
In 1987​, 522 comma 000 people worked in the air transportation industry. In 2003​, the number was 480 comma 000. ​(a) Find a li
umka2103 [35]

Answer:

the linear equation is :

y= -2625x+5737875

and 440000 employees will be in year 2271

Step-by-step explanation:

in order to find the linerar equation let us first convert the given data into (x,y ) co-ordinates i.e

x1= 1987 y1= 522,000  

and

 

x2= 2003, y2 = 480000

according to two point form:

y-y1 = (y2-y1) \frac{x-x1}{x2-x1}

In this example we have x1=1987 , y1=522000 , x2=2003 and y2=480000. So,

y - 522000 = \frac{480000-522000}{2003-1987}  (x-1987)\\y- 522000 = -2625(x-1987)\\y- 522000= -2625x+5215875\\\\y= -2625x+5737875

now to find the year when there will be 440000 employs working , we simply put y= 440000 in the above derived equation

440000= -2625x+ 5737875\\\\2526x = 5737875 -440000\\2526x =  5736555\\x= \frac{5736555}{2526} \\x= 2271

7 0
3 years ago
3(5z-7)+2(9z-11)=4(8z-7)-111
NISA [10]
3(5z - 7) + 2(9z - 11) = 4(8z - 7) - 111
15z - 21 + 18z - 22 = 32z - 28 - 111
33z - 43 = 32z - 139
33z - 32z = -139 + 43
z = - 96
5 0
3 years ago
Read 2 more answers
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