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3 years ago

Which decimal is less than 0.12 and greater than 0.008?

Mathematics

2 answers:

Pepsi [2]3 years ago

5 0

Answer:

D: 0.009

Step-by-step explanation:

Because 0.12 is 12 if you remove the zeros but D is correct because there are lots of place holders (0's) meaning its less then because it has more place holders compared to the others that don't have any place holders

grin007 [14]3 years ago

4 0

0.009 because every number is over 0.008 but 0.009 is the only one less than 0.12

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The sum of x and 2 and itr is and algebraic expression

Masja [62]

Sum is add
sum of x and 2 means x+2
nothing to it

3 0

3 years ago

Laura paddles in her canoe at a speed of 6 mph for 6 miles. She then hops on her windsurfer and sails for 12 miles at a speed of

Allisa [31]

Answer: C, 3 HOURS

Step-by-step explanation:

she canoed for 1 hour and windsurfed for 2 hours

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3 years ago

Silvia was growing some plants. She measured the height, in inches, of the plants and made thisline plot to show her data:

FromTheMoon [43]

Answer:

The answer is C.

Step-by-step explanation:

The equivalents to 1/4 are 2/8, 3/12, 4/16 etc. So the fractions after 1/4 are higher than 1/4. Then you count how many 'x's are in the columns for those measurements and you will get 6.

5 0

3 years ago

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

3 years ago

A carnival ride is in the shape of a wheel with a radius of 25 feet. The wheel has 20 cars attached to the center of the wheel.

Vladimir79 [104]

Centre angle will be 360° as its totally a circle.

radius=r=25ft

Angle between two cars=360/20=18°

Arc length=L

$\\ \sf\longmapsto L=\dfrac{\theta}{360}(2\pi r)$

$\\ \sf\longmapsto L=\dfrac{18}{360}(2\pi(25))$

$\\ \sf\longmapsto L=\dfrac{1}{20}(50\pi)$

$\\ \sf\longmapsto L=2.5\pi ft$

Now

Area be A

$\\ \sf\longmapsto A=\dfrac{1}{2}Lr^2$

$\\ \sf\longmapsto A=\dfrac{1}{2}(2.5\pi)(25)^2$

$\\ \sf\longmapsto A=625(2.5)\pi\dfrac{1}{2}$

$\\ \sf\longmapsto A=1562.5\pi/2$

$\\ \sf\longmapsto A=781\pi ft^2=$

4 0

3 years ago