Answer:
its 10n
Step-by-step explanation:
Answer:
81.85% of the workers spend between 50 and 110 commuting to work
Step-by-step explanation:
We can assume that the distribution is Normal (or approximately Normal) because we know that it is symmetric and mound-shaped.
We call X the time spend from one worker; X has distribution N(μ = 70, σ = 20). In order to make computations, we take W, the standarization of X, whose distribution is N(0,1)

The values of the cummulative distribution function of the standard normal, which we denote
, are tabulated. You can find those values in the attached file.

Using the symmetry of the Normal density function, we have that
. Hece,

The probability for a worker to spend that time commuting is 0.8185. We conclude that 81.85% of the workers spend between 50 and 110 commuting to work.
Answer:
D) 26.04 ft
Step-by-step explanation:
Let's set up a equation with two ratios:

Plug in the given lengths into the equation:

We can solve this using cross multiplication (multiply the numerator of the first fraction by the denominator of the second and the numerator of the second by the denominator of the first):

D) 26.04 ft
Hi
85% ⇒ 68
100% ⇒ x
85x = 100·(68)
85x = 6800
x = 6800/85
x = 80
Answer: 80
Answer:
compressed it by 3 in the x direction
it stretched it by 2 in the y direction
Step-by-step explanation:
f(x) = |x|
then it became
g(x) = |3x| so it compressed it by 3 in the x direction
h(x) = 2 |3x| so it stretched it by 2 in the y direction