April: 13.5+8.7+11.1
March: (13.5+8.7+11.1)÷2
May: 4×(13.5+8.7+11.1)
April: 33.3
March: 33.3÷2=16.65
May: 4×33.3=133.2
Proportion: 133.2÷16.65=8
so 133.2:16.65 is equal to 1:8. So she rode 8 times Farther in May then in March.
The month that she rode the most is May the least is March. If you want me to do step by step on the addition I will.
Let's say a = number of ordered soups, b = number of ordered sandwiches.
Then 4.5a + 7.75b = 113.50, and a and b are integers between 0 and 18 inclusive.
How do we tackle this? If all ordered soup, the cost would be $81, so we'll have at least 4 sandwiches. If all ordered sandwich, the cost would be $139.5, so at most 15 sandwiches were ordered. You also know an even number of sandwiches was ordered, to let the price end at 50 cent.
If you brute-force from 4,6,8,10,12 to 14 sandwiches, you find the answer at 10 sandwiches and 8 soups.
10*7.75 + 8*4.50 = 113.50
For this case what you can do is the following rule of three:
m ---> 100%
x ----> 115%
Clearing the value of x we have:
x = (115/100) * (m)
x = 1.15 * (m)
Answer:
a simplified expression to represent the number of members this year is:
x = 1.15 * (m)
