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Sophie [7]
2 years ago
12

John jogs 30miles every week .there are 52 weeks in a year. How many miles does john jog in a year?

Mathematics
2 answers:
tia_tia [17]2 years ago
8 0

Answer:

John would be running 1560 miles in a year

Colt1911 [192]2 years ago
6 0
It is 1,560 because you multiply 30x52 and you get 1,560
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A store manager wants to determine how much to pay her employees. The number of hours the employees work is x, and the hourly wa
Ivanshal [37]

Answer:

<em>The employees will work for 1 hour, will earn $5 per hour and will be paid $5</em>

Step-by-step explanation:

<u>System of Equations</u>

The number of hours the employees work is x.

And the hourly wage that they are paid is y. The store manager is willing to pay the employees a wage given by the equation

10y-30x=20

The business owner states that the employees should be paid a wage given by the equation

6y+30x=60

Adding both equations we have:

16y = 80

Dividing by 16:

y = 80/16 = 5

Substituting into the first equation:

10*5-30x=20

Operating and simplifying:

50-30x=20

50 - 20 = 30x

30x = 30

x = 30/30 = 1

Thus, the employees will work for 1 hour, will earn $5 per hour and will be paid $5

6 0
2 years ago
Which equation represents a proportional relationship?
Sergeu [11.5K]
There is no equations 
7 0
3 years ago
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What is 2.95 expressed as a fraction?
Kaylis [27]
B or c because its lower than the denominator
8 0
3 years ago
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If f'(0) = 5 and F(x) = f(3x), what is F'(0)?
Llana [10]

Answer:

\displaystyle F'(0) = 15

Step-by-step explanation:

We are given that:

f'(0) = 5 \text{ and } F(x) = f(3x)

And we want to find F'(0).

First, find F(x):

\displaystyle F'(x) = \frac{d}{dx}\left[ f(3x)]

From the chain rule:

\displaystyle \begin{aligned} F'(x) &= f'(3x) \cdot \frac{d}{dx} \left[ 3x\right] \\ \\ &= 3f'(3x)\end{aligned}

Then:

\displaystyle \begin{aligned} F'(0) & = 3f'(3(0)) \\ \\ & = 3f'(0) \\ \\ & = 3(5) \\ \\ & = 15\end{aligned}

In conclusion, F'(0) = 15.

7 0
2 years ago
Read 2 more answers
If you can see it will plzzz help
Serhud [2]

Answer:

You should probably change the language on your computer if thats what your asking

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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