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3 years ago

Find the product. (-4-3-2)^2

Mathematics

1 answer:

kumpel [21]3 years ago

7 0

Answer:

Hi there!

Your answer is:

Step-by-step explanation:

First, simplify within parentheses.

-4-3-2 = -7-2 = -9

(-9)^2

The negative is within the parentheses, so it goes away when squared

(-9)^2 = -9× -9= 81

Hope this helps

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Rufina [12.5K]

Answer: a = 23, b = 21, c = 136

Step-by-step explanation:

8 0

3 years ago

What are the solutions of x squared 6 x minus 6 = 10?.

Anika [276]

Answer:

x=-8 OR X=2

Step-by-step explanation:

X²+6X-6=10

X²+6X-16=0

X²+8X-2X-16

X(X+8)-2(X+8)

X+8=0 X-2=0

X=-8 OR X=2

8 0

2 years ago

The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$

Hence, the test statistic is t= -0.90.

7 0

3 years ago

What is 3/10 and 1/5 by using common

astra-53 [7]

Answer:

Step-by-step explanation:

5*2=10

10*1=10

so 1/5=2/10

3 0

3 years ago

Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d

gtnhenbr [62]

Answer:

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

Step-by-step explanation:

Evaluate:

$\dfrac{b-3a}{bc^{2}-d}$

When a=-4, b=2, c=-3, and d =4

Solution:

Substitute, a=-4, b=2, c=-3, and d =4 in above expression we get

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{2-3(-4)}{2(-3)^{2}-4}\\\\=\dfrac{2+12}{18-4}\\\\$

$\dfrac{b-3a}{bc^{2}-d}=\dfrac{14}{14}=1$

Therefore, the variable expression when a=-4, b=2, c=-3, and d =4 is

$\dfrac{b-3a}{bc^{2}-d}=1$

6 0

3 years ago