The picture is difficult to read, but it looks like
∠ADB = 2x²
∠ACB = 10x
These two angles have equal measure, so you have
2x² = 10x
2x(x -5) = 0 . . . . . subtract 10x and factor
x = 0, or x = 5
The measure of arc AB is twice the measure of either inscribed angle, so would be
arc AB = 2×10x
= 2×10×5
= 100 . . . . . degrees
Arc AB is 100°.
I believe your answer is -0.25n+0.75
I believe the first quartile would be 24 and the third would be 8. Sorry if this wasn't correct. I haven't done this in a while.
Hope it helps
8.333333
let x=8.33333 and 10x=83.33333
10x-x=83.333-8.333
9x=75
x=75/9
x=25/3
x=8 1/3
Now if you meant:
8.383838 then
100x-x=838.3838-8.3838
99x=830
x=830/99
The answer would be 0.90 and 0.900
