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3 years ago

Solve the exponential equation for x 625=5^(7x-3)

Mathematics

2 answers:

LekaFEV [45]3 years ago

8 0

$625 = 5^{7x-3} \\$

Create equivalent bases:

$625 = 5^4\\5^4 = 5^{7x-3}$

Since the bases are equal, then exponent1 = exponent2 in order for this equation to be true.

$7x - 3 = 4\\7x = 7\\x = 1$

Check the answer:

$5^{7(1) - 3}\\5^{7 - 3}\\5^4\\625 = 625$

Our answer is correct,

x = 1

trapecia [35]3 years ago

4 0

Answer:

x=1

Step-by-step explanation:

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Laqueta has three times as many quarters as Pablo if they each spend $.50 Laqueta will have five times as many quarters as Pablo

masya89 [10]

Answer:

Number of quarters with Pablo = 4

Number of quarters with Laqueta = 12

Step-by-step explanation:

Given that:

Laqueta has three times as many quarters as Pablo.

They both spend $0.50.

After that Laqueta will have 5 times as many quarters as Pablo.

To find:

Number of quarters with Laqueta and Pablo now?

Solution:

Let number of quarters with Laqueta = $x$

Let number of quarters with Pablo = $y$

As per given statement:

$x=3y ..... (1)$

In $0.50, there are 2 quarters:

After spending $0.50, number of quarters left with both of them:

Number of quarters left with Laqueta = $x$ - 2 = $3y-2$

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As per given statement:

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Number of quarters with Pablo = 4

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