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Vesnalui [34]
3 years ago
13

I need helpppp.........

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer

n║m

Step-by-step explanation:

Hope this is helpful!

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Equation for ( 6, 13) ( 7900, 5 )
tia_tia [17]

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

y=mx+b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following points through which the line passes:

(x_ {1}, y_ {1}) :( 6,13)\\(x_ {2}, y_ {2}): (7900,5)

We find the slope of the line:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {5-13} {7900-6} = \frac {-8} {7894} = - \frac {4} {3947}

Thus, the equation of the line is of the form:

y = - \frac {4} {3947} x + b

We substitute one of the points and find b:

13 = - \frac {4} {3947} (6) + b\\13 = - \frac {24} {3947} + b\\13+ \frac {24} {3947} = b\\b = \frac {51335} {3947}

Finally, the equation is:

y = - \frac {4} {3947} x + \frac {51335} {3947}

Answer:

y = - \frac {4} {3947} x + \frac {51335} {3947}

5 0
4 years ago
Help me with this one please
Drupady [299]

Step-by-step explanation:

1cm = 16 km

Distance between York and London = 23.1 cm

<em>Now the real distance between </em><em>York </em><em>and </em><em>London </em><em>=</em><em> </em><em>2</em><em>3</em><em>.</em><em>1</em><em> </em><em>*</em><em> </em><em>1</em><em>6</em>

<em>=</em><em> </em><em>3</em><em>6</em><em>9</em><em>.</em><em>6</em><em> </em><em>km </em>

6 0
4 years ago
A basket contains six apples, three oranges, ten corn, four pears and six peaches, You randomly select a fruit. What is the cond
Alla [95]

Answer:

b. 15%

Step-by-step explanation:

because it is 3 oranges and 3 is equal to 15%

5 0
2 years ago
you and four of your nine classmates received an A on your math test, what is the simplest fraction of students that scored an A
alex41 [277]
The simplest fraction is 4/5
8 0
3 years ago
Read 2 more answers
Write the left side of each equation as a product of linear factors, and state the solutions.
Amiraneli [1.4K]

Answer:

a). x_{1}=1, x_{2}=1,x_{3}=1

b). x_{1}=2, x_{2}=2, x_{3}=2

c). x_{1} = \sqrt{-5}, x_{2} = \sqrt{-5}, x_{2} = \sqrt{-2},x_{4} = \sqrt{-2}

Step-by-step explanation:

a.

x^{3}-1=0\\x^{3}=1\\ x=(1 )^{\frac{1}{3} }

x=1

b.

x^{3}+8=0\\x^{3}=-8\\ x=(-8 )^{\frac{1}{3} }

x= 2i

c.

x^{4} +7x^{2} +10=0\\x^{4}=u^{2} \\x^{2}=u\\ u^{2}+7u+10=0\\

Using

\frac{-b+/-\sqrt{7^{2}-4*a*c } }{2*a}

u=\frac{-7+/-\sqrt{7^{2}-4*10}}{2}=-\frac{7}{2} +/- \frac{\sqrt{49-40} }{2} \\ u=-\frac{7}{2} +/- \frac{3}{2} \\u_{1}= -5\\u_{2}= -2

But u is no the factor is x so:

x=\sqrt{u}\\ x_{1} =\sqrt{-5} =5i\\ x_{2} =\sqrt{-2} =2i

Check:

(\sqrt{5i})^{4} +7*(\sqrt{5i})^{2}  +10=0\\25*i^{4} +7*5*i^{2}+10=0\\ 25*1+7*5*-1+10\\25-35+10=0\\0=0

4 0
4 years ago
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