Answer:
10/13 ≈ 76.9%
Step-by-step explanation:
P(A∪B) = P(A) +P(B) -P(A∩B)
P(plays basketball ∪ plays baseball)
= P(plays basketball) +P(plays baseball) -P(plays both)
P(plays basketball ∪ plays baseball) = 16/26 +9/26 -5/26 = 20/26 = 10/13
P(plays basketball or baseball) = 10/13 ≈ 76.9%
Answer:
Answer is 0.5
Step-by-step explanation:
The text implies that the number of traffic accidents determines the number of ambulances required on the road. Hence, 1 traffic accident requires 1 ambulance.
The time slot and time of day remain same in both the text and the question.
The average or mean number of accidents is 1.1
QUESTION: What then is the probability that there is need for exactly 2 ambulances on that road and in that time frame?
In other words, what is the probability that there'll be 2 accidents on that road and in that time frame?
Since the mean number of accidents is 1.1, 2 is above the mean.
Probability of 1.1 accidents is 1, since that's the mean (expected value).
Probability of 2 accidents is 1/2 which is = 0.5
Answer:
C. 6
Step-by-step explanation:
to divide by a fraction multiply by the recirpocal of that fraction.
8/3 ÷ 9/4
reduce the numbers with GCF 4 which equals 2/3 x 9
reduce the numbers with GCF 3 which equals 2x3= 6
3/4 of a sandwich for each sandwich will amount to 6 sandwiches and 8 children can eat
Answer:
Step-by-step explanation:
Assuming the question is x^2 + 6x = 27x, subtract 6x from both sides. x^2 = 21x. Then, divide both sides by x and you get x= 0, 21
