The probability is 2/3.
The probability of a sum greater than 5 given the first roll is 3 is given by
P(sum>5|first 3)=P(first 3 and sum>5)/P(first 3)
The probability of rolling a 3 first and having a sum > 5 is 4/36 = 1/9.
The probability of rolling a 3 first is 6/36 = 1/6.
1/9÷1/6 = 1/9×6/1 = 6/9 = 2/3
Answer:
As x increases, y increases. As x decreases, y decreases.
Step-by-step explanation:
Basically the answer is option 2