When adding numbers which way do you usually work
1 answer:
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Answer:
- Find the coefficients using ax^2 + bx + c = 0
a = 4
b = 7
c = 0
- Make the coefficient equal 1. But how do we do that? Division.
4n² + 7n = 0
4/4n² + 7n/4 = 0/4
- Simplify
= n² + 7/4n = 0
a = 1
b = 7/4
c = 0
- Complete the square using b/2².
b = 7/4
(b/2)² = (7/4 ÷ 2)²
Use fraction rule.
7/4 ÷ 2² = 7/4² / 2²
<em>square the numbers</em>
7/4² / 2² = 49/16 ÷ 4
49/16 ÷ 4 = 49/16 × 1/4
49/16 × 1/4 = 49/64
Add to both sides of the equation using 49/64
b = 7/4
b/2 = 7/4 ÷ 2
<em>simplify</em>
b/2 = 7 ÷ (4 × 2)
<em>simplify(arithmetic)</em>
b/2 = 7/8
n² + 7/4n + 49/64 = 49/64
(n + 7/8)² = 49/64
- Solve for the unknown x
Next, cancel out the square on the left side.
Subtract 7/8 from both of the sides.
Simplify the left side.
<em>That wraps it up for this equation. Hope it helped!</em>