3-3=b+3-3
solve each side
0=b
The answer is:
545>322
540 <997
The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
Read more about combination at:
brainly.com/question/11732255
#SPJ1
Answer:
I don't know sorry but I really want brainliest
Time = distance / speed
time = (1000 mi)/(126.3702 mi/h) ≈ 7.913 h
