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3 years ago

Jenny buys a new shirt that costs $22. If sales tax is 8%, how much will the tax be?

Mathematics

2 answers:

kap26 [50]3 years ago

8 0

Answer:

$1.76

Step-by-step explanation:

$22 * .08 = $1.76

alexandr402 [8]3 years ago

5 0

Step-by-step explanation:

Find 8% of $22 and add it on to $22, that will be your answer. :) If this helped I hope you give brainliest:)

You might be interested in

What 3 even numbers add up to 54

katovenus [111]

Well, let's see . . . . .

2, 4, and 48
2, 6, and 46
2, 8, and 44
2, 10, and 42
2, 12, and 40
2, 14, and 38
2, 16, and 36
2, 18, and 34
.
.
and so on and so forth.
When I keep going and do all of them, I get 46 answers altogether.

If you need the even numbers to be consecutive,
then they're 16, 18, and 20 .

5 0

3 years ago

Read 2 more answers

A shipping container in the shape of a rectangular prism is 60 feet long, 45 1/2 feet wide, and 14 feet tall. What is the volume

Rufina [12.5K]

C. 38,200 ft^3

Why you ask? Good question, how you solve volume is l•w•h=v (length•width•height=volume) so it was 60•45.5•14=38,200

Hope this helps!

6 0

3 years ago

Read 2 more answers

-0.75-(-2/5)+0.4+(-3/4)

RSB [31]

-0.75-(-2/5)+0.4+(-3/4) = -0.7 simplified, how I got this answer can be found below in 16 steps.

1 - First thing we want to do is remove the parentheses.

-0.75 - (-2/5) + 0.4 - 3/4

2 - Then we simplify, multiply -1 by -1.

-0.75 + 1 (2/5) + 0.4 - 3/4

3 - Then multiply 2/5 by 1.

-0.75 + 2/5 + 0.4 - 3/4

4 - Then we want to write - 0.75/1 as a fraction with a common denominator, we do this by multiplying by 5/5.

-0.75/1 * 5/5 + 2/5 + 0.4 - 3/4

5 - Then we write each expression with a common denominator of 5, we multiply each one by a factor of one.

-0.75 * 5/1*5 + 2/5 + 0.4 - 3/4

6 - Then we multiply 5 by 1.

-0.75 * 5 / 5 + 2/5 + 0.4 - 3/4

7 - Then we combine the numerators over the common denominator.

-0.75*5+2/5+0.4-3/4

8 - We multiply -0.75 by 5.

-3.75 + 2/5 + 0.4 - 3/4

9 - Then we add -3.75 and 2.

-1.75/5+0.4-3/4

10 - And then we divide -1.75 by 5.

-0.35 + 0.4 - 3/4

11 - Then add -0.35 and 0.4.

0.05 - 3/4

12 - We then write 0.05/1 as a fraction with a common denominator, we do this via multiplying it by 4/4.

0.05/1 * 4/4 - 3/4

13 - Then we write each expression with a common denominator of 4, through multiplying each by a factor of 1.

0.05 * 4/4 - 3/4

14 - We combine the numerators over the common denominator.

0.05 * 4 - 3 / 4

15 - We simplify.

-2.8 / 4

16 - Then we divide -2.8 / 4

The final answer is -0.7

6 0

3 years ago

On a spelling test of 100 words, most students spell between 68 and 75 words correctly. Which term best describes the only stude

Aleks [24]

Answer:

B, outlier

Step-by-step explanation:

8 0

2 years ago

A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed

AURORKA [14]

Answer:

A 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Step-by-step explanation:

We are given that Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured.

For the 25-mil film, the sample data result is: Mean Standard deviation 1.15 0.11 and For the 20-mil film the data yield: Mean Standard deviation 1.06 0.09.

Firstly, the pivotal quantity for finding the confidence interval for the difference in population mean is given by;

P.Q. = $\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean speed for the 25-mil film = 1.15

$\bar X_1$ = sample mean speed for the 20-mil film = 1.06

$s_1$ = sample standard deviation for the 25-mil film = 0.11

$s_2$ = sample standard deviation for the 20-mil film = 0.09

$n_1$ = sample of 25-mil film = 8

$n_2$ = sample of 20-mil film = 8

$\mu_1$ = population mean speed for the 25-mil film

$\mu_2$ = population mean speed for the 20-mil film

Also, $s_p =\sqrt{\frac{(n_1-1)s_1^{2}+ (n_2-1)s_2^{2}}{n_1+n_2-2} }$ = $\sqrt{\frac{(8-1)\times 0.11^{2}+ (8-1)\times 0.09^{2}}{8+8-2} }$ = 0.1005

Here for constructing a 98% confidence interval we have used a Two-sample t-test statistics because we don't know about population standard deviations.

So, 98% confidence interval for the difference in population means, ( $\mu_1-\mu_2$ ) is;

P(-2.624 < $t_1_4$ < 2.624) = 0.98 {As the critical value of t at 14 degrees of

freedom are -2.624 & 2.624 with P = 1%}

P(-2.624 < $\frac{(\bar X_1 -\bar X_2)-(\mu_1- \mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < 2.624) = 0.98

P( $-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < $2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < ) = 0.98

P( $(\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < ( $\mu_1-\mu_2$ ) < $(\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ) = 0.98

98% confidence interval for ( $\mu_1-\mu_2$ ) = [ $(\bar X_1-\bar X_2)-2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ , $(\bar X_1-\bar X_2)+2.624 \times {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ]

= [ $(1.15-1.06)-2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }$ , $(1.15-1.06)+2.624 \times {0.1005 \times \sqrt{\frac{1}{8}+\frac{1}{8} } }$ ]

= [-0.042, 0.222]

Therefore, a 98% confidence interval estimate for the difference in mean speed of the films is [-0.042, 0.222].

Since the above interval contains 0; this means that decreasing the thickness of the film doesn't increase the speed of the film.

7 0

3 years ago